Solution:Step 1: Evaluate the && operator with array and falseIn PHP, non-empty arrays are truthy, but truthy && false is false.Step 2: Apply ternary operatorSince the condition is false, the ternary returns 'No'.Final Answer:No, because the && operator evaluates to false -> Option AQuick Check:Trut

[Solved] Given the code:$arr = [1, 2, 3]; $result = $arr && false ? 'Yes' : 'No'; echo $result;What is the output and why? | PHP

PHP - Operators

Given the code:

$arr = [1, 2, 3];
$result = $arr && false ? 'Yes' : 'No';
echo $result;

What is the output and why?

ANo, because the && operator evaluates to false

BNo output, script halts

CError, because arrays cannot be used with &&

DYes, because $arr is truthy and combined with false

Step-by-Step Solution

Solution:

Step 1: Evaluate the && operator with array and false
In PHP, non-empty arrays are truthy, but truthy && false is false.
Step 2: Apply ternary operator
Since the condition is false, the ternary returns 'No'.
Final Answer:
No, because the && operator evaluates to false -> Option A
Quick Check:
Truthy && false = false, ternary returns 'No' [OK]

Quick Trick: && returns false if any operand is false [OK]

Common Mistakes:

Assuming array && false is true
Thinking arrays cause errors with &&
Confusing ternary outputs
Ignoring operator precedence

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Given the code:

Step 1: Evaluate the && operator with array and false

Step 2: Apply ternary operator

Final Answer:

Quick Check:

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