[Solved] Find the error in this PHP code snippet:$x = '10';if ($x = 10) { echo 'Match';} else { echo 'No Match';} | PHP

PHP - Type Handling

Find the error in this PHP code snippet:

$x = '10';
if ($x = 10) {
    echo 'Match';
} else {
    echo 'No Match';
}

AUsing assignment (=) instead of comparison (==) in if condition

BMissing semicolon after echo statement

CUsing double quotes instead of single quotes

DVariable $x is not defined

Step-by-Step Solution

Solution:

Step 1: Check if condition operator
The condition uses = which assigns 10 to $x instead of comparing.
Step 2: Understand effect of assignment in if
Assignment returns 10 (truthy), so 'Match' always prints, ignoring original $x value.
Final Answer:
Using assignment (=) instead of comparison (==) in if condition -> Option A
Quick Check:
Assignment in if condition = Using assignment (=) instead of comparison (==) in if condition [OK]

Quick Trick: Use == or === for comparison, not = [OK]

Common Mistakes:

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