[Solved] Identify the error in this PHP function declaration:function setName(?string name) { echo $name; } — Ans: Missing dollar sign ($) before parameter name. | PHP

PHP - Functions

Identify the error in this PHP function declaration:

function setName(?string name) {
    echo $name;
}

AMissing dollar sign ($) before parameter name.

BNullable types cannot be used with strings.

CFunction must return a value.

DParameter cannot be nullable without default value.

Step-by-Step Solution

Solution:

Step 1: Check parameter syntax
In PHP, all variable names must start with a dollar sign $. The parameter name is missing $.
Step 2: Validate nullable type usage
Nullable types like ?string are valid. The function does not require a return value. Parameters can be nullable without default values.
Final Answer:
Missing dollar sign ($) before parameter name. -> Option A
Quick Check:
Parameter variables need $ prefix [OK]

Quick Trick: Always prefix parameter names with $ in PHP functions [OK]

Common Mistakes:

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