[Solved] Find the error in this PHP code snippet:$x = true;$y = false;if ($x || ! $y) { echo 'True'; else { echo 'False';} | PHP

PHP - Operators

Find the error in this PHP code snippet:

$x = true;
$y = false;
if ($x || ! $y) {
    echo 'True';
 else {
    echo 'False';
}

AMissing closing brace for if block

BMissing semicolon after echo statement

CIncorrect use of logical OR operator

DMissing closing parenthesis in if condition

Step-by-Step Solution

Solution:

Step 1: Check the if statement syntax
The if condition has correct parentheses and logical operators.
Step 2: Check the braces for if-else blocks
The if block opens with { but does not have a closing } before the else block starts.
Final Answer:
Missing closing brace for if block -> Option A
Quick Check:
Braces must match for if-else [OK]

Quick Trick: Count opening and closing braces carefully [OK]

Common Mistakes:

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