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You want to write a PHP script that outputs 'Ready' only after the entire PHP code finishes running. Which approach ensures this behavior?

hard📝 Application Q8 of 15
PHP - Request Lifecycle
You want to write a PHP script that outputs 'Ready' only after the entire PHP code finishes running. Which approach ensures this behavior?
AUse multiple PHP blocks with echo 'Ready'; in the first block.
BPlace echo 'Ready'; after all PHP code inside the last PHP block before closing.
CWrite echo 'Ready'; outside any PHP tags in plain HTML.
DPut echo 'Ready'; before the opening PHP tag.
Step-by-Step Solution
Solution:
  1. Step 1: Understand PHP execution order

    PHP executes code inside PHP tags in order. To output after all code, echo must be last inside PHP.
  2. Step 2: Evaluate options

    Place echo 'Ready'; after all PHP code inside the last PHP block before closing. places echo 'Ready'; at the end of PHP code, ensuring it runs last and outputs correctly.
  3. Final Answer:

    Place echo 'Ready'; after all PHP code inside the last PHP block before closing. -> Option B
  4. Quick Check:

    Last echo inside PHP block outputs final text [OK]
Quick Trick: Echo last inside PHP block to output final text [OK]
Common Mistakes:
  • Placing echo outside PHP tags expecting PHP output
  • Echoing 'Ready' too early in multiple blocks
  • Trying to echo before PHP starts

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