[Solved] What is wrong with this PHP code snippet?if ($value > 20) echo 'High'; echo 'Done'; — Ans: The second echo runs regardless of the if condition due to missing braces | PHP

PHP - Conditional Statements

What is wrong with this PHP code snippet?

if ($value > 20)
  echo 'High';
  echo 'Done';

APHP requires semicolon after if statement

BThe condition syntax is incorrect, missing parentheses

CThe variable $value is not defined

DThe second echo runs regardless of the if condition due to missing braces

Step-by-Step Solution

Solution:

Step 1: Analyze the if statement structure
Without braces, only the first statement after if is controlled by it.
Step 2: Identify effect on second echo
Second echo runs always, which may be unintended.
Final Answer:
The second echo runs regardless of the if condition due to missing braces -> Option D
Quick Check:
Braces needed to group multiple statements [OK]

Quick Trick: Use braces to group multiple statements [OK]

Common Mistakes:

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