[Solved] Find the bug in this PHP code:$var = '';if (is_null($var)) { echo 'Null';} else { echo 'Not Null';} — Ans: Empty string is not null, so condition is wrong | PHP

PHP - Type Handling

Find the bug in this PHP code:

$var = '';
if (is_null($var)) {
  echo 'Null';
} else {
  echo 'Not Null';
}

AMissing semicolon after echo

BEmpty string is not null, so condition is wrong

Cis_null() cannot be used on strings

DVariable $var is not defined

Step-by-Step Solution

Solution:

Step 1: Understand is_null() behavior
is_null() returns true only if variable is exactly null, empty string is not null.
Step 2: Analyze condition result
Since $var is '', condition is false, so 'Not Null' is printed.
Final Answer:
Empty string is not null, so condition is wrong -> Option B
Quick Check:
is_null('') = false [OK]

Quick Trick: Empty string is not null [OK]

Common Mistakes:

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