[Solved] Identify the error in this PHP function definition:function greet($name = "Guest", $age) { echo "Hello $name, age $age"; } | PHP

PHP - Functions

Identify the error in this PHP function definition:

function greet($name = "Guest", $age) {
  echo "Hello $name, age $age";
}

AFunction cannot have default parameters

BDefault parameter must be last or followed only by default parameters

CMissing semicolon after echo statement

DVariable names cannot have default values

Step-by-Step Solution

Solution:

Step 1: Check parameter order rules
In PHP, parameters with default values must come after parameters without defaults.
Step 2: Identify the error
Here, $name has a default but $age does not, and $age comes after $name, which is invalid syntax.
Final Answer:
Default parameter must be last or followed only by default parameters -> Option B
Quick Check:
Default parameters must be at the end [OK]

Quick Trick: Place all default parameters after non-default ones [OK]

Common Mistakes:

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