Given this nested loop, how can you modify it to stop all loops when $k == 1?

hard📝 Application Q8 of 15

PHP - Loops

Given this nested loop, how can you modify it to stop all loops when $k == 1?

for ($i = 0; $i < 3; $i++) {
    for ($j = 0; $j < 3; $j++) {
        for ($k = 0; $k < 3; $k++) {
            if ($k == 1) {
                // What break statement stops all loops here?
            }
            echo "$i$j$k ";
        }
    }
}

Acontinue 3;

Bbreak 2;

Cbreak 3;

Dbreak;

Step-by-Step Solution

Solution:

Step 1: Count nested loops
There are three nested loops: $i, $j, and $k.
Step 2: Use break with correct level
To stop all three loops when $k == 1, use break 3; inside the innermost loop.
Final Answer:
break 3; -> Option C
Quick Check:
Break 3 exits all three loops [OK]

Quick Trick: Use break n; where n = number of nested loops to exit all [OK]

Common Mistakes:

Using break 2; exits only two loops
Using break; exits only innermost loop
Using continue instead of break

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Given this nested loop, how can you modify it to stop all loops when $k == 1?

Step 1: Count nested loops

Step 2: Use break with correct level

Final Answer:

Quick Check:

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