[Solved] Find the error in this PHP code snippet:for ($i = 0; $i — Ans: break 3; is invalid because only 2 loops exist. | PHP

PHP - Loops

Find the error in this PHP code snippet:

for ($i = 0; $i < 3; $i++) {
    for ($j = 0; $j < 3; $j++) {
        if ($i == $j) {
            break 3;
        }
        echo "$i,$j\n";
    }
}

Abreak 3; is invalid because only 2 loops exist.

Bbreak 3; should be break 2; to exit both loops.

Cbreak 3; causes infinite loop.

DNo error, code runs fine.

Step-by-Step Solution

Solution:

Step 1: Count nested loops
There are 2 nested loops: outer and inner.
Step 2: Check break level usage
Using break 3; tries to break out of 3 loops, but only 2 exist, causing a fatal error.
Final Answer:
break 3; is invalid because only 2 loops exist. -> Option A
Quick Check:
break n must be ≤ nested loops count [OK]

Quick Trick: Break level cannot exceed nested loops count [OK]

Common Mistakes:

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