Feature engineering basics in Pandas - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a new column 'age_squared' by squaring the 'age' column.

Pandas

df['age_squared'] = df['age'] [1] 2

Drag options to blanks, or click blank then click option'

A**

B+

C*

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '**' will add 2 instead of squaring.

Using '*' will multiply by 2, not square.

We use the ** operator to raise numbers to a power in pandas.

2fill in blank

medium

Complete the code to create a new column 'is_adult' that is True if 'age' is 18 or more, else False.

Pandas

df['is_adult'] = df['age'] [1] 18

Drag options to blanks, or click blank then click option'

A<=

B>=

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' will select ages less than or equal to 18, which is opposite.

Using '==' will only select age exactly 18.

The operator >= checks if age is greater than or equal to 18.

3fill in blank

hard

Fix the error in the code to create a new column 'bmi' as weight divided by height squared.

Pandas

df['bmi'] = df['weight'] / (df['height'] [1] 2)

Drag options to blanks, or click blank then click option'

A+

B*

C**

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using '*' multiplies height by 2, not squares it.

Using '//' does integer division, which is incorrect here.

To square height, we use the power operator **.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 characters.

Pandas

lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will select words shorter than 3, opposite of requirement.

Using 'word' as value stores the word itself, not its length.

We want the length of each word as the value, so use len(word). We only want words longer than 3, so use >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values only for items with positive values.

Pandas

result = [1]: [2] for k, v in data.items() if v [3] 0

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'k' instead of 'k.upper()' keeps keys lowercase.

Using '<' or '<=' filters wrong items.

Keys are converted to uppercase with k.upper(). Values are v. We filter for values greater than zero using >.

Practice

1. What is the main purpose of feature engineering in pandas?

easy

A. To create new useful columns from existing data

B. To delete unnecessary rows from the dataset

C. To change the data type of columns

D. To visualize data using charts

Solution

1. Step 1: Understand feature engineering definition

   Feature engineering means creating new columns that help models learn better.

2. Step 2: Compare options with definition

   Only To create new useful columns from existing data matches the purpose of creating new useful columns from existing data.

3. Final Answer:

   To create new useful columns from existing data -> Option A

4. Quick Check:

   Feature engineering = create new columns [OK]

Hint: Feature engineering = making new columns from old data [OK]

Common Mistakes:

• Confusing feature engineering with data cleaning
• Thinking it only changes data types
• Mixing it up with data visualization

2. Which of the following is the correct way to create a new column total as sum of columns 2a and 2b in a pandas DataFrame df?

easy

A. df['total'] <- df['2a'] + df['2b']

B. df.total = df.2a + df.2b

C. df['total'] == df['2a'] + df['2b']

D. df['total'] = df['2a'] + df['2b']

Solution

1. Step 1: Recall pandas syntax for new column

   Use df['new_col'] = expression to create new columns.

2. Step 2: Check each option

   df['total'] = df['2a'] + df['2b'] uses correct syntax. df.total = df.2a + df.2b misses brackets, A uses wrong operator, D uses comparison operator.

3. Final Answer:

   df['total'] = df['2a'] + df['2b'] -> Option D

4. Quick Check:

   New column = df['col'] = ... [OK]

Hint: Use df['col'] = ... to add new columns [OK]

Common Mistakes:

• Using == instead of = for assignment
• Using <- which is not Python syntax
• Accessing columns without brackets

3. Given the DataFrame df below, what will be the output of df['age_group'] after this code?

import pandas as pd
df = pd.DataFrame({'age': [15, 22, 37, 45]})
df['age_group'] = pd.cut(df['age'], bins=[0, 18, 35, 60], labels=['child', 'young_adult', 'adult'])

medium

A. [child, young_adult, young_adult, adult]

B. [child, child, young_adult, adult]

C. [child, young_adult, adult, adult]

D. [child, young_adult, adult, young_adult]

Solution

1. Step 1: Understand pd.cut bins and labels

   Bins: 0-18 = child, 18-35 = young_adult, 35-60 = adult.

2. Step 2: Assign each age to bin

   15 -> child, 22 -> young_adult, 37 -> adult, 45 -> adult.

3. Final Answer:

   [child, young_adult, adult, adult] -> Option C

4. Quick Check:

   Age 37 and 45 fall in adult bin [OK]

Hint: Match values to bins to find labels [OK]

Common Mistakes:

• Misunderstanding bin edges (inclusive/exclusive)
• Assigning wrong labels to ages
• Confusing order of labels

4. What is wrong with this code to create a new column year from a datetime column date in DataFrame df?

df['year'] = df['date'].year

medium

A. There is no error; the code is correct

B. You must use dt.year to access year from datetime column

C. You should use df.year = df.date.year instead

D. The column date must be converted to string first

Solution

1. Step 1: Recall how to extract year from datetime column

   Use df['date'].dt.year to get year from pandas datetime column.

2. Step 2: Identify error in code

   Code uses df['date'].year which is invalid; .year is not attribute of Series.

3. Final Answer:

   You must use dt.year to access year from datetime column -> Option B

4. Quick Check:

   Use df['date'].dt.year for datetime year [OK]

Hint: Use .dt accessor for datetime column parts [OK]

Common Mistakes:

• Using .year directly on Series instead of .dt.year
• Converting datetime to string unnecessarily
• Assigning to df.year instead of df['year']

5. You have a DataFrame df with columns height_cm and weight_kg. You want to create a new feature bmi using the formula bmi = weight_kg / (height_m)^2, where height in meters is height_cm divided by 100. Which code correctly creates the bmi column?

hard

A. df['bmi'] = df['weight_kg'] / (df['height_cm'] / 100) ** 2

B. df['bmi'] = df['weight_kg'] / df['height_cm'] ** 2 / 10000

C. df['bmi'] = df['weight_kg'] * (df['height_cm'] / 100) ** 2

D. df['bmi'] = df['weight_kg'] / (df['height_cm'] * 100) ** 2

Solution

1. Step 1: Convert height from cm to meters

   Height in meters = height_cm / 100.

2. Step 2: Apply BMI formula correctly

   BMI = weight_kg / (height_m)^2 = weight_kg / (height_cm / 100)^2.

3. Step 3: Check each option

   df['bmi'] = df['weight_kg'] / (df['height_cm'] / 100) ** 2 matches formula exactly. Others have wrong operations or units.

4. Final Answer:

   df['bmi'] = df['weight_kg'] / (df['height_cm'] / 100) ** 2 -> Option A

5. Quick Check:

   BMI formula with height in meters = weight / height² [OK]

Hint: Divide height_cm by 100 before squaring for BMI [OK]

Common Mistakes:

• Forgetting to convert cm to meters
• Multiplying instead of dividing
• Incorrect order of operations