pandas.to_numeric() with the error handling configurationto_numeric() for safe conversion in Pandas - Mini Project: Build & Apply
sales_data with one column named 'sales' containing these exact string values: '100', '200', 'N/A', '300', 'unknown'.Use pd.DataFrame() with a dictionary where the key is 'sales' and the value is the list of strings.
error_handling and set it to the string 'coerce' to tell pandas to convert invalid values to NaN.Set error_handling to the string 'coerce' to convert invalid entries to NaN.
pandas.to_numeric() on the sales_data['sales'] column with the errors=error_handling argument. Save the result in a new column called sales_data['sales_numeric'].Use pd.to_numeric() with the errors parameter set to error_handling.
sales_data['sales_numeric'] column to see the numeric conversion results.Use print() to display the sales_numeric column.
Practice
What does the pandas.to_numeric() function do?
Solution
Step 1: Understand the purpose of
This function is designed to convert data to numeric types like int or float.to_numeric()Step 2: Recognize safe conversion feature
It can handle errors safely by converting invalid parsing to NaN if specified.Final Answer:
It converts values to numeric types safely, handling errors. -> Option AQuick Check:
to_numeric() = safe numeric conversion [OK]
- Thinking it sorts data
- Confusing it with DataFrame creation
- Assuming it converts numbers to strings
Which of the following is the correct syntax to convert a pandas Series s to numeric, turning errors into NaN?
?Solution
Step 1: Recall error handling options in
The parameterto_numeric()errorscan be 'raise', 'ignore', or 'coerce'.Step 2: Identify which option converts bad data to NaN
'coerce' converts invalid parsing to NaN safely.Final Answer:
pd.to_numeric(s, errors='coerce') -> Option CQuick Check:
errors='coerce' = convert errors to NaN [OK]
- Using errors='drop' which is invalid
- Confusing errors='ignore' with coercion
- Forgetting to specify errors parameter
What will be the output of this code?
import pandas as pd
s = pd.Series(['10', '20', 'abc', '30'])
s_num = pd.to_numeric(s, errors='coerce')
s_num.tolist()Solution
Step 1: Convert series with invalid string using errors='coerce'
The string 'abc' cannot convert to number, so it becomes NaN.Step 2: Check the output list format
Valid numbers become floats, invalid become NaN, so output is [10.0, 20.0, nan, 30.0].Final Answer:
[10.0, 20.0, nan, 30.0] -> Option DQuick Check:
Invalid strings become NaN with errors='coerce' [OK]
- Expecting original string 'abc' to remain
- Expecting integer output instead of float
- Thinking it raises an error
Identify the error in this code snippet:
import pandas as pd
s = pd.Series(['1', '2', 'three'])
s_num = pd.to_numeric(s, errors='drop')
print(s_num)Solution
Step 1: Check valid values for 'errors' in to_numeric()
Valid values are 'raise', 'coerce', and 'ignore'. 'drop' is invalid.Step 2: Understand the error caused by invalid parameter
Using 'drop' causes a TypeError or ValueError because it's not supported.Final Answer:
The parameter 'errors' does not accept 'drop'. -> Option AQuick Check:
errors='drop' is invalid in to_numeric() [OK]
- Assuming 'drop' removes bad data automatically
- Ignoring error messages
- Confusing Series content with syntax error
You have a DataFrame df with a column 'price' containing strings like '100', '200', and some invalid entries like 'unknown'. You want to convert 'price' to numeric, replacing invalid entries with 0. Which code snippet achieves this?
Solution
Step 1: Convert 'price' column with errors='coerce'
This converts invalid strings to NaN safely.Step 2: Replace NaN with 0 using
This replaces all invalid entries with 0 as required.fillna(0)Final Answer:
df['price'] = pd.to_numeric(df['price'], errors='coerce').fillna(0) -> Option BQuick Check:
Use errors='coerce' + fillna(0) to replace bad data [OK]
- Using errors='ignore' which keeps invalid strings
- Using dropna() which removes rows instead of replacing
- Using errors='raise' which causes exceptions
Ready to prove it?
Pass the test and this pattern moves unknown
