Sorting by index means arranging the rows or columns of a DataFrame or Series based on their index labels in ascending or descending order.
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beginner
Which pandas method is used to sort a DataFrame by its index?
The method sort_index() is used to sort a DataFrame or Series by its index labels.
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intermediate
How do you sort a DataFrame by its index in descending order?
Use df.sort_index(ascending=False) to sort the DataFrame by its index in descending order.
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advanced
What happens if you use sort_index() on a DataFrame with a MultiIndex?
The sort_index() method sorts the DataFrame by all levels of the MultiIndex by default, arranging rows based on the hierarchical index labels.
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intermediate
Can you sort columns by their index labels using sort_index()?
Yes, by setting the parameter axis=1 in sort_index(), you can sort the columns of a DataFrame by their index labels.
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Which pandas method sorts a DataFrame by its index?
Asort_index()
Bsort_values()
Corder_by()
Dindex_sort()
✗ Incorrect
The correct method to sort by index in pandas is sort_index().
How do you sort a DataFrame's columns by their index labels?
Adf.sort_values(axis=1)
Bdf.sort_index(axis=0)
Cdf.sort_columns()
Ddf.sort_index(axis=1)
✗ Incorrect
Setting axis=1 in sort_index() sorts the columns by their index labels.
What does df.sort_index(ascending=False) do?
ASorts the DataFrame by index in descending order
BSorts the DataFrame by values in descending order
CSorts the DataFrame by columns in ascending order
DSorts the DataFrame by index in ascending order
✗ Incorrect
The parameter ascending=False sorts the index in descending order.
If a DataFrame has a MultiIndex, how does sort_index() behave by default?
ASorts only the first level of the MultiIndex
BSorts by all levels of the MultiIndex
CDoes not sort MultiIndex DataFrames
DSorts only the last level of the MultiIndex
✗ Incorrect
By default, sort_index() sorts all levels of a MultiIndex.
What is the default sorting order of sort_index()?
ARandom order
BDescending order
CAscending order
DNo sorting
✗ Incorrect
The default sorting order for sort_index() is ascending.
Explain how to sort a pandas DataFrame by its index and how to change the sorting order.
Think about the method name and the parameter that controls ascending or descending.
You got /3 concepts.
Describe how to sort the columns of a DataFrame by their index labels.
Remember axis=0 is rows, axis=1 is columns.
You got /3 concepts.
Practice
(1/5)
1. What does sorting by index in pandas do?
easy
A. It changes the data values to alphabetical order.
B. It filters rows based on a condition.
C. It removes duplicate rows from the DataFrame.
D. It arranges data rows or columns based on their labels.
Solution
Step 1: Understand the meaning of sorting by index
Sorting by index means arranging the data based on the row or column labels, not the data values.
Step 2: Compare options with the definition
Only It arranges data rows or columns based on their labels. correctly describes sorting by index as arranging rows or columns by their labels.
Final Answer:
It arranges data rows or columns based on their labels. -> Option D
Quick Check:
Sorting by index = arrange by labels [OK]
Hint: Sorting by index means ordering by labels, not values [OK]
Common Mistakes:
Confusing sorting by index with sorting by values
Thinking it filters or removes data
Assuming it changes data values
2. Which of the following is the correct syntax to sort a DataFrame df by its row index in descending order without changing the original DataFrame?
easy
A. df.sort_index(ascending=False, inplace=False)
B. df.sort_index(axis=1, ascending=False)
C. df.sort_index(ascending=True, inplace=False)
D. df.sort_index(ascending=False, inplace=True)
Solution
Step 1: Identify parameters for sorting by index
To sort by row index descending, use ascending=False. To avoid changing original, use inplace=False.
Step 2: Check each option
df.sort_index(ascending=False, inplace=False) uses ascending=False and inplace=False, which matches the requirement. df.sort_index(ascending=False, inplace=True) changes original (inplace=True). df.sort_index(ascending=True, inplace=False) sorts ascending. df.sort_index(axis=1, ascending=False) sorts columns (axis=1).
Final Answer:
df.sort_index(ascending=False, inplace=False) -> Option A
Quick Check:
Descending + no inplace = ascending=False, inplace=False [OK]
Hint: Use inplace=False to keep original unchanged [OK]
Common Mistakes:
Using inplace=True when original should not change
Confusing ascending=True with descending order
Sorting columns instead of rows by mistake
3. Given the DataFrame df with index labels [3, 1, 2] and values ["a", "b", "c"], what will df.sort_index() return as the index order?
medium
A. [a, b, c]
B. [1, 2, 3]
C. [3, 2, 1]
D. [c, b, a]
Solution
Step 1: Understand default sort_index behavior
By default, sort_index sorts row labels in ascending order.
Step 2: Apply sorting to index [3, 1, 2]
Sorting ascending gives [1, 2, 3]. Values remain associated with their labels.
Final Answer:
[1, 2, 3] -> Option B
Quick Check:
Default sort_index sorts index ascending [OK]
Hint: Default sort_index sorts index ascending [OK]
Common Mistakes:
Confusing index labels with values
Assuming sort_index sorts values instead of index
Thinking sort_index reverses order by default
4. You run df.sort_index(axis=2) on a DataFrame but get an error. What is the likely cause?
medium
A. axis=2 is invalid; axis must be 0 or 1.
B. sort_index does not accept axis parameter.
C. DataFrame index labels are missing.
D. inplace parameter is required.
Solution
Step 1: Check valid axis values for sort_index
sort_index accepts axis=0 (rows) or axis=1 (columns) only.
Step 2: Identify error cause with axis=2
axis=2 is invalid and causes an error.
Final Answer:
axis=2 is invalid; axis must be 0 or 1. -> Option A
Quick Check:
axis must be 0 or 1 in sort_index [OK]
Hint: axis can only be 0 (rows) or 1 (columns) [OK]
Common Mistakes:
Using axis values other than 0 or 1
Assuming sort_index ignores invalid axis
Forgetting axis parameter is optional but must be valid
5. You have a DataFrame df with a multi-level index (two levels). How do you sort df by the second level of the index in ascending order without changing the original DataFrame?
hard
A. df.sort_values(level=1, ascending=True)
B. df.sort_index(level=0, ascending=True, inplace=True)
C. df.sort_index(level=1, ascending=True, inplace=False)
D. df.sort_index(axis=1, level=1)
Solution
Step 1: Understand sorting multi-level index
Use sort_index with level parameter to specify which index level to sort.
Step 2: Choose correct parameters
To sort by second level (level=1), ascending order, and keep original unchanged, use inplace=False.
Final Answer:
df.sort_index(level=1, ascending=True, inplace=False) -> Option C
Quick Check:
Sort multi-level index by level=1, inplace=False [OK]
Hint: Use level parameter to sort multi-level index [OK]
Common Mistakes:
Using sort_values instead of sort_index for index sorting
Sorting wrong index level (level=0 instead of 1)
Using inplace=True when original should not change
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