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Setting a column as index in Pandas - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to set the 'Name' column as the index of the DataFrame.

Pandas
df = df.[1]('Name')
Drag options to blanks, or click blank then click option'
Areset_index
Bset_index
Cdrop
Drename
Attempts:
3 left
💡 Hint
Common Mistakes
Using reset_index instead of set_index.
Trying to rename the column instead of setting it as index.
2fill in blank
medium

Complete the code to set the 'ID' column as index without keeping it as a column.

Pandas
df = df.set_index('ID', [1]=True)
Drag options to blanks, or click blank then click option'
Adrop
Bkeep
Cinplace
Dappend
Attempts:
3 left
💡 Hint
Common Mistakes
Using keep=True which keeps the column.
Confusing inplace with drop.
3fill in blank
hard

Fix the error in the code to set 'Date' as index inplace.

Pandas
df.[1]('Date', inplace=True)
Drag options to blanks, or click blank then click option'
Aset_index
Breset_index
Cdrop
Drename
Attempts:
3 left
💡 Hint
Common Mistakes
Using reset_index which resets the index instead of setting it.
Trying to use drop as a method.
4fill in blank
hard

Fill both blanks to set 'User' as index and keep the column in the DataFrame.

Pandas
df = df.set_index([1], [2]=False)
Drag options to blanks, or click blank then click option'
A'User'
Bdrop
Ckeep
D'Name'
Attempts:
3 left
💡 Hint
Common Mistakes
Using drop=True which removes the column.
Using the wrong column name.
5fill in blank
hard

Fill all three blanks to set 'Email' as index, drop the column, and do it inplace.

Pandas
df.[1]([2], drop=[3], inplace=True)
Drag options to blanks, or click blank then click option'
Aset_index
B'Email'
CTrue
DFalse
Attempts:
3 left
💡 Hint
Common Mistakes
Using drop=False which keeps the column.
Not using inplace=True and expecting the DataFrame to change.

Practice

(1/5)
1. What does the set_index() method do in pandas?
easy
A. It sorts the DataFrame by a column.
B. It deletes a column from the DataFrame.
C. It adds a new column to the DataFrame.
D. It sets a specified column as the index of the DataFrame.

Solution

  1. Step 1: Understand the purpose of set_index()

    The set_index() method changes the row labels to the values of a specified column.
  2. Step 2: Compare with other options

    Options A, B, and D describe different DataFrame operations, not setting the index.
  3. Final Answer:

    It sets a specified column as the index of the DataFrame. -> Option D
  4. Quick Check:

    set_index() changes row labels to a column [OK]
Hint: Remember: set_index() changes row labels to a column [OK]
Common Mistakes:
  • Confusing set_index() with drop() method
  • Thinking set_index() adds a new column
  • Assuming set_index() sorts data
2. Which of the following is the correct syntax to set the column 'Name' as the index of DataFrame df without modifying df itself?
easy
A. df.set_index('Name', inplace=True)
B. df.set_index('Name')
C. df.set_index(Name, inplace=False)
D. df.set_index('Name', drop=False)

Solution

  1. Step 1: Understand inplace parameter

    By default, inplace=False, so df.set_index('Name') returns a new DataFrame without changing df.
  2. Step 2: Analyze options

    df.set_index('Name', inplace=True) modifies df inplace. df.set_index('Name', inplace=False) is invalid because inplace=False is default and usually omitted. df.set_index('Name', drop=False) keeps the column but does not specify inplace, so it returns a new DataFrame.
  3. Final Answer:

    df.set_index('Name') -> Option B
  4. Quick Check:

    Default inplace=False means returns new DataFrame [OK]
Hint: Omit inplace to keep original DataFrame unchanged [OK]
Common Mistakes:
  • Using inplace=True when wanting a new DataFrame
  • Confusing drop parameter with inplace
  • Adding invalid parameters
3. Given the DataFrame df below:
   ID  Score
0  101     88
1  102     92
2  103     85

What will be the output of df.set_index('ID')?
medium
A.
     ID  Score
0  101     88
1  102     92
2  103     85
B.
   ID  Score
0  101     88
1  102     92
2  103     85
C.
     Score
ID          
101      88
102      92
103      85
D.
   Score
ID       
0     88
1     92
2     85

Solution

  1. Step 1: Understand set_index('ID')

    This sets the 'ID' column as the index, so 'ID' values become row labels and are no longer columns.
  2. Step 2: Check output format

    The resulting DataFrame shows 'Score' as the only column, indexed by 'ID' values 101, 102, 103.
  3. Final Answer:

    Score ID 101 88 102 92 103 85 -> Option C
  4. Quick Check:

    set_index moves column to index =
         Score
    ID          
    101      88
    102      92
    103      85
    [OK]
Hint: Index column moves from data to row labels [OK]
Common Mistakes:
  • Expecting the index column to remain as a data column
  • Confusing output with original DataFrame
  • Misreading index as a new column
4. You run the code:
df.set_index('Age', inplace=True)

but get a KeyError: 'Age'. What is the most likely cause?
medium
A. The column 'Age' does not exist in the DataFrame.
B. You forgot to import pandas.
C. You need to reset the index before setting a new one.
D. The inplace parameter must be False.

Solution

  1. Step 1: Understand KeyError meaning

    A KeyError means the specified key (column) is not found in the DataFrame.
  2. Step 2: Analyze options

    The column 'Age' does not exist in the DataFrame. correctly identifies the missing column. You forgot to import pandas. is unrelated to KeyError. You need to reset the index before setting a new one. is unnecessary; you can set any existing column as index. The inplace parameter must be False. is incorrect; inplace can be True or False.
  3. Final Answer:

    The column 'Age' does not exist in the DataFrame. -> Option A
  4. Quick Check:

    KeyError means missing column [OK]
Hint: Check column names before set_index to avoid KeyError [OK]
Common Mistakes:
  • Assuming inplace=True causes KeyError
  • Ignoring column name typos
  • Thinking reset_index is required first
5. You have a DataFrame df with columns ['City', 'Population', 'Area']. You want to set 'City' as the index but keep it as a column too. Which code achieves this?
hard
A. df.set_index('City', drop=False, inplace=True)
B. df.set_index('City', inplace=True)
C. df.set_index('City', drop=True, inplace=False)
D. df.set_index('City', keep=True)

Solution

  1. Step 1: Understand drop parameter

    By default, drop=True removes the column from data when setting it as index. To keep it, use drop=False.
  2. Step 2: Apply inplace to modify original DataFrame

    Using inplace=True changes df directly.
  3. Step 3: Analyze options

    df.set_index('City', drop=False, inplace=True) correctly uses drop=False and inplace=True. df.set_index('City', inplace=True) drops the column. df.set_index('City', drop=True, inplace=False) returns new DataFrame but drops column. df.set_index('City', keep=True) uses invalid parameter keep.
  4. Final Answer:

    df.set_index('City', drop=False, inplace=True) -> Option A
  5. Quick Check:

    drop=False keeps column when setting index [OK]
Hint: Use drop=False to keep column when setting index [OK]
Common Mistakes:
  • Forgetting drop=False to keep the column
  • Using invalid parameters like keep=True
  • Not using inplace when wanting to modify original DataFrame
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