Selecting rows by condition in Pandas - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to select rows where the 'age' column is greater than 30.

Pandas

filtered_df = df[df['age'] [1] 30]

Drag options to blanks, or click blank then click option'

A>

B<

C==

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will select rows with age less than 30.

Using '==' will select rows where age is exactly 30.

We use the greater than operator > to select rows where 'age' is more than 30.

2fill in blank

medium

Complete the code to select rows where the 'score' column is equal to 100.

Pandas

perfect_scores = df[df['score'] [1] 100]

Drag options to blanks, or click blank then click option'

A==

B<

C>

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '==' causes syntax errors.

Using '!=' selects rows where score is not 100.

The equality operator == checks if 'score' is exactly 100.

3fill in blank

hard

Fix the error in the code to select rows where 'height' is less than 170.

Pandas

short_people = df[df['height'] [1] 170]

Drag options to blanks, or click blank then click option'

A>=

B==

C=>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=>' which is not a valid Python operator.

Using '>=' selects rows with height greater or equal to 170.

The correct operator for 'less than' is <. The option '=>' is invalid syntax.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if the length is greater than 3.

Pandas

lengths = {word: [1] for word in words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Blen(word) > 3

Cword.startswith('a')

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using a condition unrelated to length.

The dictionary maps each word to its length using len(word). The condition filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their scores only if the score is greater than 50.

Pandas

result = [1]: [2] for word, score in data.items() if [3]

Drag options to blanks, or click blank then click option'

Aword.upper()

Bscore

Cscore > 50

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase words as keys instead of uppercase.

Not filtering scores correctly.

The dictionary keys are uppercase words using word.upper(). The values are scores. The condition filters scores greater than 50.

Practice

1. What does the expression df[df['age'] > 30] do in pandas?

easy

A. Deletes rows where the 'age' column is greater than 30

B. Selects columns where the 'age' value is greater than 30

C. Selects rows where the 'age' column is greater than 30

D. Sorts the DataFrame by the 'age' column

Solution

1. Step 1: Understand the condition inside the brackets

   The condition df['age'] > 30 creates a True/False mask for each row based on the 'age' value.

2. Step 2: Apply the condition to select rows

   Using df[condition] returns only rows where the condition is True, i.e., 'age' > 30.

3. Final Answer:

   Selects rows where the 'age' column is greater than 30 -> Option C

4. Quick Check:

   Condition filters rows [OK]

Hint: Use df[condition] to filter rows by True/False mask [OK]

Common Mistakes:

• Thinking it selects columns instead of rows
• Confusing filtering with sorting
• Using parentheses incorrectly around conditions

2. Which of the following is the correct syntax to select rows where column 'score' equals 100?

easy

A. df[df.score = 100]

B. df[df['score'] = 100]

C. df[df['score'] === 100]

D. df[df['score'] == 100]

Solution

1. Step 1: Identify correct equality operator in pandas

   In pandas, to compare values, use double equals ==, not single = or triple ===.

2. Step 2: Check correct column access syntax

   Using df['score'] is correct and safe for all column names.

3. Final Answer:

   df[df['score'] == 100] -> Option D

4. Quick Check:

   Use == for comparison and brackets for column [OK]

Hint: Use df[df['col'] == value] with double equals for condition [OK]

Common Mistakes:

• Using single = instead of == for comparison
• Using triple === which is invalid in Python
• Accessing columns without quotes when name has special chars

3. Given the DataFrame:

import pandas as pd
data = {'name': ['Ann', 'Bob', 'Cara', 'Dan'], 'age': [25, 35, 30, 40]}
df = pd.DataFrame(data)

What is the output of df[df['age'] >= 30]?

medium

A. Rows with names Bob, Cara, and Dan

B. Rows with names Ann and Bob

C. Rows with names Ann and Cara

D. Rows with names Dan only

Solution

1. Step 1: Evaluate the condition df['age'] >= 30

   This condition is True for ages 35 (Bob), 30 (Cara), and 40 (Dan).

2. Step 2: Select rows where condition is True

   Rows with names Bob, Cara, and Dan are returned.

3. Final Answer:

   Rows with names Bob, Cara, and Dan -> Option A

4. Quick Check:

   age >= 30 selects Bob, Cara, Dan [OK]

Hint: Check condition True rows, then list their names [OK]

Common Mistakes:

• Including Ann who is 25 (less than 30)
• Confusing >= with >
• Misreading the DataFrame data

4. What is wrong with this code to select rows where 'score' is above 50?

df[df['score'] > 50 && df['age'] < 30]

medium

A. Using && instead of & for combining conditions

B. Missing parentheses around each condition

C. Using single & instead of &&

D. Using | instead of & for and condition

Solution

1. Step 1: Check operator for combining conditions in pandas

   In pandas, use single ampersand & for 'and', not double ampersand &&.

2. Step 2: Confirm correct syntax

   Correct syntax is df[(df['score'] > 50) & (df['age'] < 30)] with parentheses and single &.

3. Final Answer:

   Using && instead of & for combining conditions -> Option A

4. Quick Check:

   Use & not && for and in pandas [OK]

Hint: Use & for and, | for or, with parentheses [OK]

Common Mistakes:

• Using && which causes syntax error
• Not adding parentheses around each condition
• Using | instead of & for and

5. You have a DataFrame df with columns 'city', 'temperature', and 'humidity'. How do you select rows where the city is 'Paris' and temperature is above 20 or humidity is below 30?

hard

A. df[(df['city'] == 'Paris') & (df['temperature'] > 20) | (df['humidity'] < 30)]

B. df[(df['city'] == 'Paris') & ((df['temperature'] > 20) | (df['humidity'] < 30))]

C. df[df['city'] == 'Paris' & df['temperature'] > 20 | df['humidity'] < 30]

D. df[df['city'] == 'Paris' and df['temperature'] > 20 or df['humidity'] < 30]

Solution

1. Step 1: Understand operator precedence and grouping

   Logical AND (&) has higher precedence than OR (|), so parentheses are needed to group OR conditions correctly.

2. Step 2: Write correct condition with parentheses

   We want city == 'Paris' AND (temperature > 20 OR humidity < 30), so use:
   df[(df['city'] == 'Paris') & ((df['temperature'] > 20) | (df['humidity'] < 30))]

3. Final Answer:

   df[(df['city'] == 'Paris') & ((df['temperature'] > 20) | (df['humidity'] < 30))] -> Option B

4. Quick Check:

   Group OR inside AND with parentheses [OK]

Hint: Use parentheses to group OR inside AND conditions [OK]

Common Mistakes:

• Missing parentheses causing wrong logic
• Using Python 'and'/'or' instead of & and |
• Not using parentheses around each condition