iloc for position-based selection in Pandas - Time & Space Complexity
We want to understand how the time it takes to select data using iloc changes as the data size grows.
How does the number of rows or columns affect the work done when using iloc?
Analyze the time complexity of the following code snippet.
import pandas as pd
df = pd.DataFrame({
'A': range(1000),
'B': range(1000, 2000),
'C': range(2000, 3000)
})
subset = df.iloc[100:200, 1:3]
This code creates a DataFrame with 1000 rows and 3 columns, then selects rows 100 to 199 and columns 1 to 2 using iloc.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Accessing each cell in the selected slice of the DataFrame.
- How many times: Once for each row and column in the selected range.
When you select more rows or columns, the work grows with the size of the slice.
| Input Size (rows x columns) | Approx. Operations |
|---|---|
| 10 x 2 | 20 |
| 100 x 2 | 200 |
| 100 x 3 | 300 |
Pattern observation: The operations grow roughly in direct proportion to the number of cells selected.
Time Complexity: O(r x c)
This means the time grows proportionally to the number of rows (r) times the number of columns (c) you select.
[X] Wrong: "Selecting data with iloc always takes the same time no matter how much data is selected."
[OK] Correct: The time depends on how many rows and columns you pick because iloc accesses each cell in the selection.
Understanding how data selection scales helps you write efficient code and explain your choices clearly in real projects and interviews.
What if we changed the selection to only one column but many rows? How would the time complexity change?
Practice
df.iloc[2] select from a pandas DataFrame df?Solution
Step 1: Understand
ilocusageilocselects rows or columns by integer position, starting at 0.Step 2: Interpret
This selects the row at position 2, which is the third row counting from zero.df.iloc[2]Final Answer:
The third row of the DataFrame by position -> Option AQuick Check:
ilocuses position, so 2 means third row [OK]
- Confusing iloc with loc (label-based selection)
- Thinking iloc uses index labels instead of positions
- Mixing row and column selection
iloc?Solution
Step 1: Understand slicing with iloc
Slices in iloc arestart:stopand select positions from start up to but not including stop.Step 2: Apply slice for first 3 rows and 2 columns
First 3 rows are positions 0,1,2 so slice is:3. First 2 columns are positions 0,1 so slice is:2.Final Answer:
df.iloc[:3, :2] -> Option DQuick Check:
Slices exclude stop, so :3 means 0,1,2 [OK]
:n to get first n positions [OK]- Using wrong slice ranges that exclude needed rows/columns
- Confusing row and column order in iloc
- Using single integers instead of slices for multiple rows/columns
import pandas as pd
df = pd.DataFrame({
'A': [10, 20, 30],
'B': [40, 50, 60],
'C': [70, 80, 90]
})
print(df.iloc[1, 2])What is the output?
Solution
Step 1: Identify row and column positions
iloc[1, 2]means row at position 1 (second row), column at position 2 (third column).Step 2: Find value at row 1, column 2
Row 1 values: A=20, B=50, C=80. Column 2 is 'C', so value is 80.Final Answer:
80 -> Option CQuick Check:
Row 1, Col 2 = 80 [OK]
- Mixing up row and column positions
- Using index labels instead of positions
- Selecting wrong column number
df.iloc[1:3, 2:1]
It aims to select rows 1 and 2 and columns 2 and 1.
Solution
Step 1: Analyze column slice 2:1
Slices select positions from start up to but not including stop. Here start=2, stop=1, which is reversed and results in an empty selection.Step 2: Check row slice 1:3
Row slice 1:3 selects rows at positions 1 and 2 correctly.Final Answer:
Column slice 2:1 is empty because stop is less than start -> Option BQuick Check:
Slices with stop less than start return empty [OK]
- Assuming reversed slices select columns in reverse
- Thinking iloc syntax is invalid for slices
- Confusing iloc with loc label slicing
df with 5 rows and 4 columns. You want to select the last 2 rows and the last 3 columns using iloc. Which code correctly does this?Solution
Step 1: Understand row positions for last 2 rows
With 5 rows (positions 0 to 4), last 2 rows are positions 3 and 4, so slice is 3:5 or equivalently -2:.Step 2: Understand column positions for last 3 columns
With 4 columns (positions 0 to 3), last 3 columns are positions 1, 2, 3, so slice is 1:4 or equivalently -3:.Step 3: Match correct iloc syntax
Using negative indices,df.iloc[-2:, -3:]would be correct. Among options,df.iloc[2:, 1:]selects rows from position 2 to end (rows 2,3,4) and columns from position 1 to end (columns 1,2,3), which includes the last 2 rows and last 3 columns.Final Answer:
df.iloc[2:, 1:] -> Option AQuick Check:
Rows 2-4 and columns 1-3 selected correctly [OK]
- Using negative slices incorrectly
- Off-by-one errors in slice ranges
- Confusing row and column slice order
Ready to prove it?
Pass the test and this pattern moves unknown
