Creating DataFrame from dictionary in Pandas - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a DataFrame from the dictionary.

Pandas

import pandas as pd

data = {'name': ['Alice', 'Bob'], 'age': [25, 30]}
df = pd.[1](data)
print(df)

Drag options to blanks, or click blank then click option'

ASeries

Blist

CDataFrame

Darray

Attempts:

3 left

💡 Hint

Common Mistakes

Using pd.Series instead of pd.DataFrame

Trying to use list or array which are not pandas constructors

Use pd.DataFrame() to create a DataFrame from a dictionary.

2fill in blank

medium

Complete the code to create a DataFrame with specified columns order.

Pandas

import pandas as pd

data = {'name': ['Alice', 'Bob'], 'age': [25, 30]}
df = pd.DataFrame(data, columns=[1])
print(df)

Drag options to blanks, or click blank then click option'

A['age']

B['name', 'age']

C['age', 'name']

D['name']

Attempts:

3 left

💡 Hint

Common Mistakes

Passing columns as a string instead of list

Using wrong column names or order

Specify columns order by passing a list of column names to columns parameter.

3fill in blank

hard

Fix the error in the code to create a DataFrame from a dictionary of lists.

Pandas

import pandas as pd

data = {'name': ['Alice', 'Bob'], 'age': [25, 30]}
df = pd.DataFrame([1])
print(df)

Drag options to blanks, or click blank then click option'

Adata.keys()

Bdata.items()

Clist(data)

Ddata

Attempts:

3 left

💡 Hint

Common Mistakes

Passing data.items() which returns a view, not a dict

Passing keys or list of keys instead of the dictionary

Pass the dictionary directly to pd.DataFrame(). Using data.items() or others will cause errors.

4fill in blank

hard

Fill both blanks to create a DataFrame from a dictionary and select only the 'age' column.

Pandas

import pandas as pd

data = {'name': ['Alice', 'Bob'], 'age': [25, 30]}
df = pd.[1](data)
age_column = df[[2]]
print(age_column)

Drag options to blanks, or click blank then click option'

ADataFrame

BSeries

C'age'

D'name'

Attempts:

3 left

💡 Hint

Common Mistakes

Using pd.Series instead of pd.DataFrame

Selecting column with wrong name or without quotes

Create DataFrame with pd.DataFrame() and select column by its name as a string.

5fill in blank

hard

Fill all three blanks to create a DataFrame from a dictionary, rename columns, and print the new DataFrame.

Pandas

import pandas as pd

data = {'name': ['Alice', 'Bob'], 'age': [25, 30]}
df = pd.[1](data)
df.columns = [[2], [3]]
print(df)

Drag options to blanks, or click blank then click option'

ADataFrame

B'First Name'

C'Age'

D'name'

Attempts:

3 left

💡 Hint

Common Mistakes

Trying to rename columns before creating DataFrame

Assigning column names without quotes or wrong number of names

Create DataFrame with pd.DataFrame(), then rename columns by assigning a list of new names to df.columns.

Practice

1. What happens when you create a pandas DataFrame from a dictionary where keys are column names and values are lists of equal length?

easy

A. The DataFrame will have rows named after the keys and columns from the list values.

B. A DataFrame is created with columns named after the keys and rows from the list values.

C. An error occurs because dictionaries cannot be converted to DataFrames.

D. Only the first key-value pair is used to create the DataFrame.

Solution

1. Step 1: Understand dictionary to DataFrame mapping

   In pandas, dictionary keys become column names and values (lists) become column data.

2. Step 2: Check list lengths

   All lists must have the same length to form rows correctly.

3. Final Answer:

   A DataFrame is created with columns named after the keys and rows from the list values. -> Option B

4. Quick Check:

   Dictionary keys = columns, lists = rows [OK]

Hint: Keys become columns, lists become rows if lengths match [OK]

Common Mistakes:

• Thinking dictionary keys become row labels
• Assuming only one key-value pair is used
• Believing dictionaries can't create DataFrames

2. Which of the following is the correct syntax to create a pandas DataFrame from a dictionary named data?

easy

A. df = pd.DataFrame(data)

B. df = pd.DataFrame.from_dict(data, orient='index')

C. df = pd.DataFrame(data, columns=['A', 'B'])

D. df = pd.DataFrame(data).to_dict()

Solution

1. Step 1: Recall basic DataFrame creation syntax

   The standard way to create a DataFrame from a dictionary is using pd.DataFrame(data).

2. Step 2: Analyze other options

   df = pd.DataFrame.from_dict(data, orient='index') changes orientation to index, which is not default; df = pd.DataFrame(data, columns=['A', 'B']) tries to specify columns but may cause errors if columns don't match; df = pd.DataFrame(data).to_dict() converts DataFrame back to dict, not creation.

3. Final Answer:

   df = pd.DataFrame(data) -> Option A

4. Quick Check:

   Use pd.DataFrame(dictionary) to create DataFrame [OK]

Hint: Use pd.DataFrame(your_dict) for quick DataFrame creation [OK]

Common Mistakes:

• Using .to_dict() instead of creating DataFrame
• Confusing orient parameter for simple dict
• Specifying columns that don't exist in dict

3. What will be the output of the following code?

import pandas as pd
data = {'Name': ['Alice', 'Bob'], 'Age': [25, 30]}
df = pd.DataFrame(data)
print(df)

medium

A. A DataFrame with rows named 'Name' and 'Age' and columns 0 and 1.

B. A dictionary printed with keys 'Name' and 'Age'.

C. An error because lists have different lengths.

D. A DataFrame with columns 'Name' and 'Age' and two rows with values Alice-25 and Bob-30.

Solution

1. Step 1: Create DataFrame from dictionary

   The dictionary keys become columns 'Name' and 'Age'. The lists provide row data.

2. Step 2: Print DataFrame

   Output shows two rows: first with 'Alice' and 25, second with 'Bob' and 30.

3. Final Answer:

   A DataFrame with columns 'Name' and 'Age' and two rows with values Alice-25 and Bob-30. -> Option D

4. Quick Check:

   Dictionary keys = columns, lists = rows [OK]

Hint: Keys = columns, lists = rows; print shows table [OK]

Common Mistakes:

• Expecting dictionary print instead of DataFrame
• Confusing rows and columns
• Assuming error due to list lengths

4. Identify the error in this code snippet that tries to create a DataFrame from a dictionary:

import pandas as pd
data = {'A': [1, 2], 'B': [3]}
df = pd.DataFrame(data)
print(df)

medium

A. Lists in the dictionary have different lengths causing a ValueError.

B. The dictionary keys are not strings.

C. pd.DataFrame() cannot take a dictionary as input.

D. The print statement is missing parentheses.

Solution

1. Step 1: Check list lengths in dictionary

   List under key 'A' has length 2, but list under 'B' has length 1.

2. Step 2: Understand DataFrame requirements

   All lists must be the same length to form rows; mismatch causes ValueError.

3. Final Answer:

   Lists in the dictionary have different lengths causing a ValueError. -> Option A

4. Quick Check:

   All lists must be equal length [OK]

Hint: Check all lists have same length before DataFrame creation [OK]

Common Mistakes:

• Ignoring list length mismatch
• Thinking keys must be non-string
• Assuming print syntax error in Python 3

5. You have a dictionary with some keys having empty lists and others with data:

data = {'X': [1, 2, 3], 'Y': [], 'Z': [4, 5, 6]}

How can you create a valid DataFrame from this dictionary?

hard

A. Remove keys with empty lists before creating the DataFrame.

B. Create the DataFrame directly; pandas fills missing columns with NaN.

C. Replace empty lists with lists of None matching other list lengths.

D. Use pd.DataFrame.from_dict(data, orient='index') to fix empty lists.

Solution

1. Step 1: Identify problem with empty lists

   Empty list for key 'Y' has length 0, others have length 3, causing mismatch.

2. Step 2: Fix by replacing empty lists

   Replace empty list with [None, None, None] to match lengths and keep column.

3. Step 3: Create DataFrame

   Now all lists have equal length; DataFrame creation succeeds with NaN or None in 'Y'.

4. Final Answer:

   Replace empty lists with lists of None matching other list lengths. -> Option C

5. Quick Check:

   All columns must have equal-length lists [OK]

Hint: Replace empty lists with None-filled lists of correct length [OK]

Common Mistakes:

• Trying to create DataFrame directly with empty lists
• Removing keys losing important data
• Misusing orient parameter for this issue