Why disk scheduling reduces seek time in Operating Systems - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the sentence to explain why disk scheduling reduces seek time.

Operating Systems

Disk scheduling reduces seek time by [1] the order of disk access requests.

Drag options to blanks, or click blank then click option'

Aoptimizing

Brandomizing

Cignoring

Ddelaying

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 'randomizing' because it sounds like mixing up requests.

Choosing 'ignoring' because it seems like skipping requests.

Disk scheduling reduces seek time by optimizing the order in which disk access requests are handled, minimizing the movement of the disk's read/write head.

2fill in blank

medium

Complete the sentence to describe what disk scheduling minimizes.

Operating Systems

Disk scheduling minimizes the [1] time of the disk's read/write head.

Drag options to blanks, or click blank then click option'

Aseek

Bwaiting

Ctransfer

Dprocessing

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing seek time with transfer time.

Choosing waiting time which is related but not the main focus.

Disk scheduling minimizes the seek time, which is the time taken for the disk's read/write head to move to the correct track.

3fill in blank

hard

Fix the error in the sentence about disk scheduling.

Operating Systems

Disk scheduling increases the [1] time by rearranging requests.

Drag options to blanks, or click blank then click option'

Aseek

Btransfer

Cwaiting

Dprocessing

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing seek time because it is related to movement.

Choosing transfer time which is about data movement, not scheduling.

The sentence is incorrect because disk scheduling reduces waiting time, not increases it. The correct term to fix the sentence is waiting time.

4fill in blank

hard

Fill both blanks to complete the explanation of disk scheduling.

Operating Systems

Disk scheduling [1] the sequence of requests to reduce [2] time.

Drag options to blanks, or click blank then click option'

Areorders

Bincreases

Cseek

Dtransfer

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 'increases' which is opposite of the goal.

Confusing seek time with transfer time.

Disk scheduling reorders the sequence of requests to reduce seek time, which helps the disk head move less and faster.

5fill in blank

hard

Fill all three blanks to explain how disk scheduling improves performance.

Operating Systems

By [1] requests based on their [2], disk scheduling [3] the total seek time.

Drag options to blanks, or click blank then click option'

Aordering

Blocation

Creduces

Dignoring

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing 'ignoring' which would not help performance.

Mixing up ordering and ignoring.

Disk scheduling improves performance by ordering requests based on their location on the disk, which reduces the total seek time needed for the disk head to move.

Practice

1. Why does disk scheduling reduce the seek time in an operating system?

easy

A. It arranges disk requests to minimize the movement of the disk head.

B. It increases the speed of the disk motor.

C. It compresses the data on the disk to reduce size.

D. It duplicates data to multiple disks for faster access.

Solution

1. Step 1: Understand what seek time means

   Seek time is the time taken for the disk head to move to the track where data is stored.

2. Step 2: How scheduling affects seek time

   Disk scheduling arranges requests so the head moves less distance, reducing seek time.

3. Final Answer:

   It arranges disk requests to minimize the movement of the disk head. -> Option A

4. Quick Check:

   Less head movement = less seek time [OK]

Hint: Disk scheduling reduces head movement to cut seek time [OK]

Common Mistakes:

• Confusing seek time with data transfer speed
• Thinking disk speed changes physically
• Assuming data compression affects seek time

2. Which of the following is a correct reason why disk scheduling algorithms reduce seek time?

easy

A. They process requests in the order they arrive without change.

B. They increase the disk's rotational speed.

C. They reorder requests to reduce the distance the disk head moves.

D. They store all data in memory to avoid disk access.

Solution

1. Step 1: Identify how disk scheduling works

   Disk scheduling algorithms reorder requests to optimize head movement.

2. Step 2: Why reordering helps

   By reordering, the disk head travels less distance, reducing seek time.

3. Final Answer:

   They reorder requests to reduce the distance the disk head moves. -> Option C

4. Quick Check:

   Reordering requests = less seek time [OK]

Hint: Reordering requests reduces head travel distance [OK]

Common Mistakes:

• Thinking requests are always processed as received
• Confusing seek time with rotational speed
• Assuming all data is cached in memory

3. Consider a disk with requests at tracks 10, 22, 20, 2, and 40. The disk head is currently at track 20. Which scheduling approach will likely reduce seek time the most?

medium

A. Processing requests in the order: 10, 22, 20, 2, 40

B. Processing requests in the order: 20, 10, 2, 22, 40

C. Processing requests in the order: 40, 22, 20, 10, 2

D. Processing requests in the order: 20, 22, 40, 10, 2

Solution

1. Step 1: Identify current head position and requests

   The head is at 20; requests are 10, 22, 20, 2, 40.

2. Step 2: Calculate seek distances for each option

   Processing requests in the order: 20, 10, 2, 22, 40 moves from 20 to 10 (10 tracks), then 10 to 2 (8 tracks), then 2 to 22 (20 tracks), then 22 to 40 (18 tracks). Total = 56 tracks, which is less than other options.

3. Final Answer:

   Processing requests in the order: 20, 10, 2, 22, 40 -> Option B

4. Quick Check:

   Minimized head movement = Processing requests in the order: 20, 10, 2, 22, 40 [OK]

Hint: Choose order minimizing total head travel [OK]

Common Mistakes:

• Ignoring current head position
• Not calculating total seek distance
• Assuming original request order is best

4. A disk scheduling algorithm is not reducing seek time as expected. Which of the following could be a likely cause?

medium

A. The algorithm processes requests strictly in arrival order without reordering.

B. The disk head speed is too fast.

C. The disk has too much free space.

D. The disk uses a cache to store frequently accessed data.

Solution

1. Step 1: Identify what reduces seek time

   Seek time reduces when requests are reordered to minimize head movement.

2. Step 2: Analyze the cause of no improvement

   If requests are processed strictly in arrival order, no optimization happens, so seek time stays high.

3. Final Answer:

   The algorithm processes requests strictly in arrival order without reordering. -> Option A

4. Quick Check:

   No reordering = no seek time reduction [OK]

Hint: No reordering means no seek time improvement [OK]

Common Mistakes:

• Blaming disk speed or free space incorrectly
• Confusing caching with seek time reduction
• Ignoring request processing order

5. A disk scheduling algorithm uses the Shortest Seek Time First (SSTF) method. If the disk head is at track 50 and requests come in at tracks 45, 10, 55, 60, and 48, what is the order of servicing requests to minimize seek time?

hard

A. 50 -> 48 -> 45 -> 55 -> 60 -> 10

B. 50 -> 10 -> 45 -> 48 -> 55 -> 60

C. 50 -> 55 -> 60 -> 48 -> 45 -> 10

D. 50 -> 48 -> 45 -> 10 -> 55 -> 60

Solution

1. Step 1: Identify closest request to current head

   From 50, closest is 48 (distance 2), then from 48 closest 45 (3), then from 45 closest 10 (35), then from 10 closest 55 (45), then 60.

2. Step 2: Follow SSTF order

   Service 48 first, then 45, then 10, then 55, then 60.

3. Final Answer:

   50 -> 48 -> 45 -> 10 -> 55 -> 60 -> Option D

4. Quick Check:

   SSTF picks nearest request each time [OK]

Hint: Always pick nearest request next in SSTF [OK]

Common Mistakes:

• Choosing requests in arrival order
• Ignoring distance when selecting next request
• Mixing up SSTF with other algorithms