Bird
Raised Fist0
Operating Systemsknowledge~10 mins

Demand paging in Operating Systems - Interactive Code Practice

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the sentence to describe demand paging.

Operating Systems
Demand paging loads a page into memory only when it is [1].
Drag options to blanks, or click blank then click option'
Areferenced
Bcreated
Cdeleted
Dwritten
Attempts:
3 left
💡 Hint
Common Mistakes
Assuming all pages are loaded at process start.
2fill in blank
medium

Complete the sentence to explain what causes a page fault.

Operating Systems
A page fault occurs when a process tries to access a page that is not currently [1] in memory.
Drag options to blanks, or click blank then click option'
Aloaded
Bdeleted
Ccreated
Dstored
Attempts:
3 left
💡 Hint
Common Mistakes
Confusing page fault with process crash.
3fill in blank
hard

Fix the error in the statement about demand paging.

Operating Systems
Demand paging loads pages of a process into memory on [1].
Drag options to blanks, or click blank then click option'
Aruntime
Bstart
Conce
Ddemand
Attempts:
3 left
💡 Hint
Common Mistakes
Thinking all pages load at process start.
4fill in blank
hard

Fill both blanks to complete the demand paging process description.

Operating Systems
When a page fault occurs, the operating system [1] the page from [2] into memory.
Drag options to blanks, or click blank then click option'
Aloads
Bdeletes
Cdisk
Dcache
Attempts:
3 left
💡 Hint
Common Mistakes
Confusing cache with disk.
5fill in blank
hard

Fill all three blanks to describe the page replacement step in demand paging.

Operating Systems
If memory is full, the OS [1] a page using a [2] algorithm and then [3] the new page.
Drag options to blanks, or click blank then click option'
Aremoves
BFIFO
Cloads
Dcreates
Attempts:
3 left
💡 Hint
Common Mistakes
Thinking the OS creates pages instead of loading them.

Practice

(1/5)
1. What is the main purpose of demand paging in operating systems?
easy
A. To load pages into memory only when they are needed
B. To load all program pages into memory before execution
C. To increase the size of physical memory
D. To prevent any page faults during program execution

Solution

  1. Step 1: Understand demand paging concept

    Demand paging means loading pages only when the program tries to use them, not before.
  2. Step 2: Compare options with concept

    To load pages into memory only when they are needed matches this idea, while others describe different or incorrect behaviors.
  3. Final Answer:

    To load pages into memory only when they are needed -> Option A
  4. Quick Check:

    Demand paging = load pages on demand [OK]
Hint: Demand paging loads pages only when accessed [OK]
Common Mistakes:
  • Thinking all pages load before execution
  • Confusing demand paging with increasing memory size
  • Assuming demand paging prevents all page faults
2. Which of the following is the correct description of a page fault in demand paging?
easy
A. When all pages are loaded into memory at once
B. When the CPU finishes executing all instructions
C. When the operating system shuts down
D. When a program tries to access a page not currently in memory

Solution

  1. Step 1: Define page fault in demand paging

    A page fault occurs when a program accesses a page that is not in physical memory.
  2. Step 2: Match definition with options

    When a program tries to access a page not currently in memory correctly describes this event; others describe unrelated events.
  3. Final Answer:

    When a program tries to access a page not currently in memory -> Option D
  4. Quick Check:

    Page fault = access missing page [OK]
Hint: Page fault happens on missing page access [OK]
Common Mistakes:
  • Confusing page fault with program completion
  • Thinking page fault happens during shutdown
  • Believing page fault means all pages loaded
3. Consider a system using demand paging. If a program accesses pages in this order: 2, 4, 2, 5, 4, which pages cause page faults assuming none are initially in memory?
medium
A. No page faults occur because pages are preloaded
B. Pages 2, 4, and 5 cause page faults
C. Pages 2 and 5 cause page faults, but not 4
D. Only page 2 causes a page fault

Solution

  1. Step 1: Identify initial memory state and page accesses

    No pages are in memory initially. Access order is 2, 4, 2, 5, 4.
  2. Step 2: Determine which accesses cause page faults

    First access to page 2 causes a fault (not in memory). Then page 4 causes a fault. The second access to page 2 is in memory, no fault. Access to page 5 causes a fault. Last access to page 4 is in memory, no fault.
  3. Final Answer:

    Pages 2, 4, and 5 cause page faults -> Option B
  4. Quick Check:

    First access to new pages = page fault [OK]
Hint: First access to each new page causes fault [OK]
Common Mistakes:
  • Assuming repeated pages cause faults
  • Thinking pages preload automatically
  • Ignoring initial empty memory state
4. A system using demand paging is experiencing frequent page faults. Which of the following could be a likely cause?
medium
A. The program accesses many pages not yet loaded
B. The CPU clock speed is too high
C. The hard disk is disconnected
D. The program is very small and fits in memory

Solution

  1. Step 1: Understand causes of frequent page faults

    Frequent page faults happen when a program accesses many pages not currently in memory.
  2. Step 2: Evaluate options for likely cause

    The program accesses many pages not yet loaded matches this cause. CPU speed or disk disconnection do not directly cause page faults. A small program fitting in memory would cause fewer faults.
  3. Final Answer:

    The program accesses many pages not yet loaded -> Option A
  4. Quick Check:

    Many new page accesses = frequent faults [OK]
Hint: Many new pages accessed cause faults [OK]
Common Mistakes:
  • Blaming CPU speed for page faults
  • Confusing hardware issues with paging faults
  • Assuming small programs cause many faults
5. In a demand paging system, if the page replacement algorithm always removes the page that was least recently used, what is the main benefit of this approach?
hard
A. It increases the total number of pages in memory
B. It prevents any page faults from occurring
C. It reduces the number of page faults by keeping frequently used pages in memory
D. It loads all pages into memory before execution

Solution

  1. Step 1: Understand least recently used (LRU) page replacement

    LRU removes the page not used for the longest time, keeping frequently used pages in memory.
  2. Step 2: Identify benefit of LRU in demand paging

    This reduces page faults by avoiding removal of pages likely to be used soon.
  3. Final Answer:

    It reduces the number of page faults by keeping frequently used pages in memory -> Option C
  4. Quick Check:

    LRU keeps frequent pages, reduces faults [OK]
Hint: LRU keeps frequent pages, lowers faults [OK]
Common Mistakes:
  • Thinking LRU increases memory size
  • Believing LRU prevents all faults
  • Confusing LRU with preloading all pages
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard