Bird
Raised Fist0
Operating Systemsknowledge~20 mins

Critical section problem in Operating Systems - Practice Problems & Coding Challenges

Choose your learning style10 modes available
Challenge - 5 Problems
🎖️
Critical Section Mastery
Get all challenges correct to earn this badge!
Test your skills under time pressure!
🧠 Conceptual
intermediate
2:00remaining
What is the main purpose of the critical section in concurrent programming?

In the context of concurrent programming, what is the primary goal of the critical section?

ATo ensure that only one process accesses a shared resource at a time to prevent data inconsistency
BTo allow multiple processes to access shared resources simultaneously without restrictions
CTo increase the speed of all processes by running them in parallel without any synchronization
DTo prevent any process from accessing the CPU during execution
Attempts:
2 left
💡 Hint

Think about what happens when multiple processes try to change the same data at once.

📋 Factual
intermediate
2:00remaining
Which of the following is NOT a necessary condition for solving the critical section problem?

Identify the condition that is not required to solve the critical section problem.

AMutual exclusion
BProgress
CBounded waiting
DInfinite waiting
Attempts:
2 left
💡 Hint

Consider what would happen if a process had to wait forever to enter the critical section.

🔍 Analysis
advanced
2:00remaining
What will happen if mutual exclusion is not enforced in the critical section?

Consider a scenario where multiple processes enter the critical section simultaneously without mutual exclusion. What is the most likely outcome?

AProcesses will execute faster without any issues
BThe system will automatically prevent conflicts without programmer intervention
CData inconsistency and race conditions may occur
DProcesses will be blocked indefinitely
Attempts:
2 left
💡 Hint

Think about what happens when two people try to write on the same paper at the same time.

❓ Comparison
advanced
2:00remaining
Which synchronization mechanism guarantees mutual exclusion by disabling interrupts?

Among the following synchronization methods, which one achieves mutual exclusion by disabling interrupts on a single processor system?

ASemaphores
BDisabling interrupts
CMonitors
DMessage passing
Attempts:
2 left
💡 Hint

Consider how the CPU can prevent context switches during critical section execution.

❓ Reasoning
expert
2:00remaining
Why is the critical section problem more challenging in multiprocessor systems compared to single processor systems?

Explain why ensuring mutual exclusion in the critical section is more complex on multiprocessor systems than on single processor systems.

ABecause disabling interrupts is ineffective since multiple processors run simultaneously
BBecause processes do not share memory in multiprocessor systems
CBecause multiprocessor systems do not require synchronization mechanisms
DBecause single processor systems have more processes running at the same time
Attempts:
2 left
💡 Hint

Think about how multiple CPUs can execute code at the same time.

Practice

(1/5)
1. What is the main goal of the critical section problem in operating systems?
easy
A. To ensure only one process accesses shared resources at a time
B. To allow multiple processes to access resources simultaneously
C. To speed up the execution of all processes
D. To prevent processes from running in parallel

Solution

  1. Step 1: Understand the critical section concept

    The critical section is a part of the program where shared resources are accessed.
  2. Step 2: Identify the problem goal

    The goal is to prevent multiple processes from entering the critical section simultaneously to avoid conflicts.
  3. Final Answer:

    To ensure only one process accesses shared resources at a time -> Option A
  4. Quick Check:

    Critical section = exclusive access [OK]
Hint: Only one process can be inside critical section at once [OK]
Common Mistakes:
  • Thinking multiple processes can safely access shared data simultaneously
  • Confusing critical section with process scheduling
  • Believing critical section speeds up all processes
2. Which of the following is a correct way to indicate a process is in its critical section using a flag variable flag[i]?
easy
A. flag[i] = true
B. flag[i] = -1
C. flag[i] = 0
D. flag[i] = false

Solution

  1. Step 1: Understand flag usage in critical section

    A flag variable is often used to indicate if a process wants to enter or is inside the critical section.
  2. Step 2: Identify correct flag value for 'in critical section'

    Setting flag[i] = true means the process is active or wants to enter the critical section.
  3. Final Answer:

    flag[i] = true -> Option A
  4. Quick Check:

    Flag true means process active [OK]
Hint: True means process wants or is inside critical section [OK]
Common Mistakes:
  • Using 0 or false to indicate active process
  • Confusing flag values with process IDs
  • Using negative values for flags
3. Consider this pseudocode for two processes P0 and P1 using flags to enter critical section:
flag[0] = true
while(flag[1]) { /* wait */ }
// critical section
flag[0] = false

What happens if both processes set their flags to true at the same time?
medium
A. Both enter critical section simultaneously
B. Both skip critical section
C. Both wait forever (deadlock)
D. One waits while the other enters critical section

Solution

  1. Step 1: Analyze the waiting condition

    Each process waits while the other's flag is true, so if both flags are true simultaneously, both wait.
  2. Step 2: Identify the outcome

    Since both wait for the other to clear their flag, neither proceeds, causing deadlock.
  3. Final Answer:

    Both wait forever (deadlock) -> Option C
  4. Quick Check:

    Both flags true = deadlock [OK]
Hint: Both flags true means both wait forever [OK]
Common Mistakes:
  • Assuming both can enter critical section simultaneously
  • Thinking one process always proceeds first
  • Ignoring the waiting loop condition
4. In the following code snippet, what is the main error that can cause the critical section problem?
flag[i] = true
while(flag[j]) {
  // do nothing
}
// critical section
flag[i] = false

Assuming two processes P0 and P1 use this code with i=0, j=1 and vice versa.
medium
A. Infinite loop if flag[j] is false
B. No mutual exclusion, both can enter critical section
C. Flag reset happens before critical section
D. Deadlock if both set flag true simultaneously

Solution

  1. Step 1: Understand the waiting condition

    Each process waits while the other process's flag is true.
  2. Step 2: Identify the error scenario

    If both processes set their flags to true simultaneously, both wait forever, causing deadlock.
  3. Final Answer:

    Deadlock if both set flag true simultaneously -> Option D
  4. Quick Check:

    Simultaneous flags true = deadlock [OK]
Hint: Both flags true causes deadlock, not mutual exclusion [OK]
Common Mistakes:
  • Thinking both can enter critical section simultaneously
  • Believing flag reset is before critical section
  • Assuming infinite loop if flag[j] is false
5. Which of the following solutions correctly solves the critical section problem by ensuring mutual exclusion, progress, and bounded waiting?
hard
A. Using a simple flag variable without turn variable
B. Peterson's algorithm using flags and turn variable
C. Both processes entering critical section simultaneously
D. Ignoring synchronization and relying on process speed

Solution

  1. Step 1: Review solution requirements

    The solution must ensure mutual exclusion, progress, and bounded waiting to solve the critical section problem correctly.
  2. Step 2: Evaluate each option

    Using a simple flag variable without turn variable lacks a turn variable, so it can cause deadlock or starvation. Peterson's algorithm using flags and turn variable uses flags and turn to guarantee all three conditions. The other options are incorrect approaches.
  3. Final Answer:

    Peterson's algorithm using flags and turn variable -> Option B
  4. Quick Check:

    Peterson's algorithm = correct solution [OK]
Hint: Peterson's algorithm uses flags + turn for safe access [OK]
Common Mistakes:
  • Ignoring the need for a turn variable
  • Assuming simple flags are enough
  • Believing processes can safely ignore synchronization
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard