Why custom ufuncs matter in NumPy - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a NumPy array.

NumPy

import numpy as np
arr = np.[1]([1, 2, 3, 4])

Drag options to blanks, or click blank then click option'

Atuple

Blist

Carray

Dmatrix

Attempts:

3 left

💡 Hint

Common Mistakes

Using Python list instead of np.array.

Trying to use np.list which does not exist.

Use np.array to create a NumPy array from a list.

2fill in blank

medium

Complete the code to define a simple custom ufunc using NumPy's vectorize.

NumPy

import numpy as np
@np.vectorize
def square(x):
    return x [1] x

Drag options to blanks, or click blank then click option'

A*

B-

C+

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition instead of multiplication.

Using division or subtraction which do not square the number.

The function squares the input by multiplying it by itself using *.

3fill in blank

hard

Fix the error in the custom ufunc that adds 10 to each element.

NumPy

import numpy as np
@np.vectorize
def add_ten(x):
    return x [1] 10

Drag options to blanks, or click blank then click option'

A/

B-

C*

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction instead of addition.

Using multiplication or division which changes the value differently.

To add 10 to each element, use the addition operator +.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

NumPy

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using < instead of > in the condition.

The dictionary maps each word to its length using len(word), and filters words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths if length is greater than 4.

NumPy

words = ['apple', 'bat', 'carrot', 'dog']
result = { [1]: [2] for w in words if len(w) [3] 4 }

Drag options to blanks, or click blank then click option'

Aw.upper()

Blen(w)

C>

Dw.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase instead of uppercase for keys.

Using < instead of > in the condition.

Mapping words instead of their lengths.

The dictionary comprehension maps each word in uppercase (w.upper()) to its length (len(w)) only if the length is greater than 4 (>).

Practice

1. Why do custom ufuncs matter in numpy?

easy

A. They let you apply your own functions element-wise on arrays easily.

B. They are used to create plots from arrays.

C. They replace the need for Python loops in all cases.

D. They automatically fix errors in array data.

Solution

1. Step 1: Understand the purpose of custom ufuncs

   Custom ufuncs allow you to apply your own math or logic functions element-wise on numpy arrays, making operations simpler.

2. Step 2: Compare with other options

   The other options describe unrelated or incorrect uses of custom ufuncs.

3. Final Answer:

   They let you apply your own functions element-wise on arrays easily. -> Option A

4. Quick Check:

   Custom ufuncs = element-wise custom functions [OK]

Hint: Custom ufuncs = your function applied to each array item [OK]

Common Mistakes:

• Thinking custom ufuncs create plots
• Believing they fix data errors automatically
• Confusing them with general Python loops

2. Which of the following is the correct way to create a custom ufunc using np.vectorize?

easy

A. ufunc = np.vectorize(my_function())

B. ufunc = np.vectorize[my_function]

C. ufunc = np.vectorize(my_function)

D. ufunc = np.vectorize{my_function}

Solution

1. Step 1: Recall the syntax of np.vectorize

   The correct syntax to create a vectorized function is np.vectorize(function_name) without brackets after the function name.

2. Step 2: Analyze each option

   ufunc = np.vectorize(my_function) uses parentheses correctly. ufunc = np.vectorize[my_function] uses square brackets which is invalid. ufunc = np.vectorize{my_function} uses curly braces which is invalid. ufunc = np.vectorize(my_function()) calls the function immediately, which is incorrect.

3. Final Answer:

   ufunc = np.vectorize(my_function) -> Option C

4. Quick Check:

   np.vectorize(function) uses parentheses [OK]

Hint: Use parentheses with np.vectorize, not brackets or braces [OK]

Common Mistakes:

• Using square brackets instead of parentheses
• Calling the function inside np.vectorize
• Using curly braces instead of parentheses

3. What is the output of this code?

import numpy as np

def square_plus_one(x):
    return x**2 + 1

vec_func = np.vectorize(square_plus_one)
arr = np.array([1, 2, 3])
print(vec_func(arr))

medium

A. [2 5 10]

B. [1 4 9]

C. [1 2 3]

D. [3 5 7]

Solution

1. Step 1: Understand the function applied

   The function squares the input and adds 1: x**2 + 1.

2. Step 2: Apply function to each array element

   For arr = [1, 2, 3]: 1**2+1=2, 2**2+1=5, 3**2+1=10.

3. Final Answer:

   [2 5 10] -> Option A

4. Quick Check:

   Square plus one applied element-wise = [2 5 10] [OK]

Hint: Apply function to each element: square then add one [OK]

Common Mistakes:

• Forgetting to add 1 after squaring
• Confusing output with original array
• Mixing up element-wise operation

4. Identify the error in this code that tries to create a custom ufunc:

import numpy as np

def add_three(x):
    return x + 3

ufunc = np.vectorize(add_three())
arr = np.array([1, 2, 3])
print(ufunc(arr))

medium

A. Missing import statement for numpy.

B. Calling add_three() inside np.vectorize instead of passing the function.

C. Using np.vectorize instead of np.frompyfunc.

D. Array arr is not defined.

Solution

1. Step 1: Check how np.vectorize is called

   np.vectorize expects a function, but add_three() calls the function immediately, passing its result instead.

2. Step 2: Understand the impact of the error

   Calling add_three() returns an integer, not a function, causing np.vectorize to fail or behave incorrectly.

3. Final Answer:

   Calling add_three() inside np.vectorize instead of passing the function. -> Option B

4. Quick Check:

   Pass function name, don't call it inside np.vectorize [OK]

Hint: Pass function name to np.vectorize, don't call it [OK]

Common Mistakes:

• Calling function inside np.vectorize
• Confusing function call with function reference
• Ignoring error messages about wrong argument type

5. You want to create a custom ufunc that returns the sign of each element in an array: -1 if negative, 0 if zero, and 1 if positive. Which code correctly creates and applies this ufunc to np.array([-2, 0, 3])?

hard

A. def sign_func(x):
if x <= 0:
return 1
else:
return -1
sign_ufunc = np.vectorize(sign_func)
print(sign_ufunc(np.array([-2, 0, 3])))

B. def sign_func(x):
return x > 0
sign_ufunc = np.vectorize(sign_func)
print(sign_ufunc(np.array([-2, 0, 3])))

C. def sign_func(x):
return x
sign_ufunc = np.vectorize(sign_func)
print(sign_ufunc(np.array([-2, 0, 3])))

D. def sign_func(x):
if x < 0:
return -1
elif x == 0:
return 0
else:
return 1
sign_ufunc = np.vectorize(sign_func)
print(sign_ufunc(np.array([-2, 0, 3])))

Solution

1. Step 1: Understand the sign function requirements

   The function must return -1 for negative, 0 for zero, and 1 for positive values.

2. Step 2: Check each option's logic

   def sign_func(x): if x < 0: return -1 elif x == 0: return 0 else: return 1 sign_ufunc = np.vectorize(sign_func) print(sign_ufunc(np.array([-2, 0, 3]))) correctly implements the conditions. def sign_func(x): return x > 0 sign_ufunc = np.vectorize(sign_func) print(sign_ufunc(np.array([-2, 0, 3]))) returns True/False, not -1/0/1. def sign_func(x): return x sign_ufunc = np.vectorize(sign_func) print(sign_ufunc(np.array([-2, 0, 3]))) returns the value itself, not the sign. def sign_func(x): if x <= 0: return 1 else: return -1 sign_ufunc = np.vectorize(sign_func) print(sign_ufunc(np.array([-2, 0, 3]))) reverses sign logic and misses zero case.

3. Final Answer:

   def sign_func(x): if x < 0: return -1 elif x == 0: return 0 else: return 1 sign_ufunc = np.vectorize(sign_func) print(sign_ufunc(np.array([-2, 0, 3]))) -> Option D

4. Quick Check:

   Correct sign logic with if-elif-else = def sign_func(x): if x < 0: return -1 elif x == 0: return 0 else: return 1 sign_ufunc = np.vectorize(sign_func) print(sign_ufunc(np.array([-2, 0, 3]))) [OK]

Hint: Use if-elif-else to cover negative, zero, positive cases [OK]

Common Mistakes:

• Returning boolean instead of -1,0,1
• Ignoring zero case
• Reversing sign conditions