Why advanced broadcasting matters in NumPy - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a 2D array of shape (3, 3) filled with ones.

NumPy

import numpy as np
array = np.[1]((3, 3))

Drag options to blanks, or click blank then click option'

Aempty

Bzeros

Cones

Dfull

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.zeros instead of np.ones

Using np.empty which creates uninitialized values

The np.ones function creates an array filled with ones.

2fill in blank

medium

Complete the code to add a 1D array to each row of a 2D array using broadcasting.

NumPy

import numpy as np
arr2d = np.array([[1, 2, 3], [4, 5, 6]])
arr1d = np.array([10, 20, 30])
result = arr2d + [1]

Drag options to blanks, or click blank then click option'

Aarr1d.reshape(3, 1)

Barr1d.T

Carr1d.reshape(1, 3)

Darr1d

Attempts:

3 left

💡 Hint

Common Mistakes

Using reshape(3, 1) which is incompatible

Using transpose which does not change shape as needed

Adding arr1d directly works because its shape (3,) broadcasts correctly across the columns of arr2d.

3fill in blank

hard

Fix the error in the code that tries to add arrays with incompatible shapes.

NumPy

import numpy as np
arr1 = np.array([[1, 2, 3], [4, 5, 6]])
arr2 = np.array([10, 20, 30])
result = arr1 + [1]

Drag options to blanks, or click blank then click option'

Aarr2.reshape(3, 1)

Barr2

Carr2.reshape(2, 3)

Darr2.reshape(1, 3)

Attempts:

3 left

💡 Hint

Common Mistakes

Using reshape(3, 1) which mismatches dimensions

Not reshaping at all causing shape error

Adding arr2 directly works because its shape (3,) broadcasts correctly across the columns of arr1.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

NumPy

words = ['data', 'ai', 'science', 'ml']
lengths = {word: [1] for word in words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Bword

Clen(word) > 3

Dword > 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of length

Using word > 3 which compares strings incorrectly

Use len(word) to get length and filter with len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths only if length is greater than 3.

NumPy

words = ['data', 'ai', 'science', 'ml']
result = { [1]: [2] for word in words if [3] }

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

Clen(word) > 3

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase instead of uppercase

Using word instead of length for values

Map uppercase words (word.upper()) to their lengths (len(word)) only if length is greater than 3 (len(word) > 3).

Practice

1. What is the main benefit of advanced broadcasting in NumPy?

easy

A. It converts arrays into lists for easier handling.

B. It automatically fixes syntax errors in code.

C. It allows operations on arrays of different shapes without explicit loops.

D. It increases the size of arrays to match memory requirements.

Solution

1. Step 1: Understand broadcasting concept

   Broadcasting lets NumPy perform element-wise operations on arrays with different shapes by automatically expanding them.

2. Step 2: Identify the main benefit

   This avoids writing loops and makes code simpler and faster.

3. Final Answer:

   It allows operations on arrays of different shapes without explicit loops. -> Option C

4. Quick Check:

   Broadcasting = operations on different shaped arrays [OK]

Hint: Broadcasting = math on different shaped arrays without loops [OK]

Common Mistakes:

• Thinking broadcasting fixes syntax errors
• Confusing broadcasting with data type conversion
• Believing broadcasting increases array size physically

2. Which of the following is the correct syntax to add a 1D array b to each row of a 2D array a using broadcasting?

easy

A. a + b

B. a * b

C. a.dot(b)

D. np.add(a.T, b)

Solution

1. Step 1: Recognize broadcasting addition

   Adding a 1D array to each row of a 2D array is done by simple addition: a + b.

2. Step 2: Check other options

   Multiplication or dot product won't add arrays element-wise. Transposing a produces incorrect results.

3. Final Answer:

   a + b -> Option A

4. Quick Check:

   Use + for element-wise addition with broadcasting [OK]

Hint: Use simple + to add arrays with compatible shapes [OK]

Common Mistakes:

• Using dot product instead of + for element-wise addition
• Transposing the 2D array a
• Using * instead of + for addition

3. What is the output of this code?

import numpy as np
x = np.array([[1, 2, 3], [4, 5, 6]])
y = np.array([10, 20, 30])
result = x + y
print(result)

medium

A. [[11 22 33]
[14 25 36]]

B. [[11 12 13]
[14 15 16]]

C. [[10 20 30]
[10 20 30]]

D. Error due to shape mismatch

Solution

1. Step 1: Understand shapes of arrays

   x is 2x3, y is 1x3. Broadcasting repeats y for each row of x.

2. Step 2: Perform element-wise addition

   Add each element of y to corresponding column in x: [[1+10, 2+20, 3+30], [4+10, 5+20, 6+30]] = [[11, 22, 33], [14, 25, 36]]

3. Final Answer:

   [[11 22 33] [14 25 36]] -> Option A

4. Quick Check:

   Broadcasting adds row-wise matching columns [OK]

Hint: Add arrays with matching trailing dimensions [OK]

Common Mistakes:

• Expecting error due to shape mismatch
• Adding only first row of y
• Confusing element-wise addition with matrix multiplication

4. Identify the error in this code snippet that tries to add a 1D array to each column of a 2D array using broadcasting:

import numpy as np
a = np.array([[1, 2, 3], [4, 5, 6]])
b = np.array([10, 20])
result = a + b
print(result)

medium

A. No error; code runs correctly

B. Shape mismatch error because b's length doesn't match a's columns

C. Syntax error due to missing parentheses

D. Type error because arrays have different data types

Solution

1. Step 1: Check shapes of arrays

   a shape is (2,3), b shape is (2,). Broadcasting tries to match trailing dimensions but 3 != 2.

2. Step 2: Understand broadcasting rules

   Broadcasting requires dimensions to be equal or one to be 1. Here, last dimension 3 and 2 differ, causing error.

3. Final Answer:

   Shape mismatch error because b's length doesn't match a's columns -> Option B

4. Quick Check:

   Broadcasting needs matching trailing dims [OK]

Hint: Trailing dimensions must match or be 1 for broadcasting [OK]

Common Mistakes:

• Assuming code runs without error
• Confusing rows and columns in shapes
• Thinking data types cause error here

5. You have a 3D array data with shape (4, 3, 2) representing 4 samples, 3 features, and 2 measurements each. You want to subtract a 1D array offset of shape (3,) from each feature across all samples and measurements. Which code correctly uses advanced broadcasting to do this?

hard

A. data - offset

B. data - offset.T

C. data - offset.reshape(2, 1, 1)

D. data - offset.reshape(1, 3, 1)

Solution

1. Step 1: Understand shapes and target operation

   data shape is (4,3,2). We want to subtract offset (shape (3,)) from features dimension (dim 1).

2. Step 2: Reshape offset for broadcasting

   Reshape offset to (1,3,1) to align with features dimension of data. This allows broadcasting across samples and measurements.

3. Step 3: Check other options

   data - offset fails (implicit treats as (1,1,3) vs (4,3,2), trailing dims 2 != 3). data - offset.T same. data - offset.reshape(2, 1, 1) size mismatch.

4. Final Answer:

   data - offset.reshape(1, 3, 1) -> Option D

5. Quick Check:

   Reshape offset to match target dimension [OK]

Hint: Reshape 1D array to (1,N,1) to broadcast on middle dim [OK]

Common Mistakes:

• Not reshaping offset and causing shape errors
• Reshaping offset incorrectly to (2,1,1)
• Assuming transpose works on 1D arrays