np.choose() for conditional selection in NumPy - Mini Project: Build & Apply

Using np.choose() for Conditional Selection

📖 Scenario: Imagine you are analyzing sales data for a small store. You want to categorize daily sales numbers into different labels based on their values.

🎯 Goal: You will create a NumPy array of sales numbers, define conditions to categorize these sales, use np.choose() to assign category labels, and finally display the categorized results.

📋 What You'll Learn

Create a NumPy array called sales with exact values: [150, 85, 230, 45, 120]

Create a NumPy array called conditions with three conditions for sales: less than 50, between 50 and 150 (inclusive), and greater than 150

Use np.choose() with the conditions array to assign categories: 'Low', 'Medium', and 'High'

Print the final array of category labels

💡 Why This Matters

🌍 Real World

Categorizing data based on conditions is common in sales analysis, customer segmentation, and many other fields.

💼 Career

Data scientists often use conditional selection to prepare data for analysis and reporting.

1

Create the sales data array

Create a NumPy array called sales with these exact values: [150, 85, 230, 45, 120].

NumPy

import numpy as np
# Create the sales array with the exact values
# Your code here

Hint

Use np.array() to create the array with the exact numbers.

2

Define conditions for sales categories

Create a NumPy array called conditions with three conditions for the sales array: sales less than 50, sales between 50 and 150 inclusive, and sales greater than 150. Use NumPy comparison operators to create boolean arrays and combine them into a single array of integers representing the condition index for each sale.

NumPy

import numpy as np
sales = np.array([150, 85, 230, 45, 120])
# Create the conditions array with values 0, 1, or 2 based on sales ranges
# Your code here

Hint

Use np.select() with a list of conditions and corresponding integer choices.

3

Use np.choose() to assign category labels

Create a list called categories with the strings 'Low', 'Medium', and 'High'. Then use np.choose() with the conditions array to create a new array called sales_categories that assigns the correct category label to each sale.

NumPy

import numpy as np
sales = np.array([150, 85, 230, 45, 120])
conditions = np.select([sales = 50) & (sales  150], [0, 1, 2])
# Create categories list and use np.choose() to assign labels
# Your code here

Hint

Use np.choose() with the conditions array and the categories list.

4

Print the sales categories

Print the sales_categories array to display the category labels for each sale.

NumPy

import numpy as np
sales = np.array([150, 85, 230, 45, 120])
conditions = np.select([sales = 50) & (sales  150], [0, 1, 2])
categories = ['Low', 'Medium', 'High']
sales_categories = np.choose(conditions, categories)
# Print the sales_categories array
# Your code here

Hint

Use print() to display the sales_categories array.

Practice

1. What does the np.choose() function do in NumPy?

easy

A. Sorts an array in ascending order

B. Selects elements from multiple arrays based on an index array

C. Calculates the mean of an array

D. Generates random numbers

Solution

1. Step 1: Understand the purpose of np.choose()

   np.choose() uses an index array to pick elements from multiple arrays at corresponding positions.

2. Step 2: Compare with other options

   Sorting, mean calculation, and random number generation are unrelated to np.choose().

3. Final Answer:

   Selects elements from multiple arrays based on an index array -> Option B

4. Quick Check:

   np.choose() = Select elements [OK]

Hint: Remember: np.choose picks from arrays using index array [OK]

Common Mistakes:

• Confusing np.choose() with sorting functions
• Thinking np.choose() calculates statistics
• Assuming np.choose() generates random values

2. Which of the following is the correct syntax to use np.choose() with an index array idx and option arrays a, b, c?

easy

A. np.choose(idx, [a, b, c])

B. np.choose([a, b, c], idx)

C. np.choose(a, b, c, idx)

D. np.choose(idx, a, b, c)

Solution

1. Step 1: Recall np.choose() parameter order

   The first argument is the index array, the second is a list of arrays to choose from.

2. Step 2: Match syntax with options

   Only np.choose(idx, [a, b, c]) matches the correct order and structure.

3. Final Answer:

   np.choose(idx, [a, b, c]) -> Option A

4. Quick Check:

   Index first, then list of arrays [OK]

Hint: Index array first, then list of arrays in np.choose() [OK]

Common Mistakes:

• Swapping index array and options
• Passing options as separate arguments instead of a list
• Using incorrect argument order

3. What is the output of the following code?

import numpy as np
idx = np.array([0, 2, 1, 0])
a = np.array([10, 20, 30, 40])
b = np.array([100, 200, 300, 400])
c = np.array([1000, 2000, 3000, 4000])
result = np.choose(idx, [a, b, c])
print(result)

medium

A. [10 2000 300 40]

B. [10 300 200 40]

C. [100 3000 2000 400]

D. [1000 300 200 40]

Solution

1. Step 1: Understand index array and options

   Index array is [0, 2, 1, 0]. Arrays are a=[10,20,30,40], b=[100,200,300,400], c=[1000,2000,3000,4000].

2. Step 2: Select elements using np.choose()

   For each position, pick from arrays based on index:
   pos0: idx=0 -> a[0]=10
   pos1: idx=2 -> c[1]=2000
   pos2: idx=1 -> b[2]=300
   pos3: idx=0 -> a[3]=40
   So result = [a[0], c[1], b[2], a[3]] = [10, 2000, 300, 40]

3. Step 3: Check options

   [10 300 200 40] incorrectly uses 300 and 200 instead of 2000 and 300. [10 2000 300 40] matches our result.

4. Final Answer:

   [10 2000 300 40] -> Option A

5. Quick Check:

   np.choose picks arrays by index, then elements by position [OK]

Hint: Index picks array, position picks element [OK]

Common Mistakes:

• Mixing up index meaning (array vs element)
• Swapping elements from wrong arrays
• Confusing np.choose with fancy indexing

4. The following code raises an error. What is the most likely cause?

import numpy as np
idx = np.array([0, 1, 2])
a = np.array([1, 2])
b = np.array([3, 4])
c = np.array([5, 6])
result = np.choose(idx, [a, b, c])
print(result)

medium

A. np.choose() requires index array to be boolean

B. Index array contains values outside the range of options

C. Index array and option arrays have incompatible shapes causing mismatch

D. np.choose() cannot handle more than two option arrays

Solution

1. Step 1: Check index array and options

   Index array is [0,1,2], which is valid for 3 options (a,b,c).

2. Step 2: Check shapes of option arrays

   a, b, c each have shape (2,), but index array has length 3. np.choose expects index and options to have compatible shapes.

3. Step 3: Identify cause of error

   Index array length 3 vs option arrays length 2 causes shape mismatch error.

4. Final Answer:

   Index array and option arrays have incompatible shapes causing mismatch -> Option C

5. Quick Check:

   Shape mismatch causes np.choose error [OK]

Hint: Ensure index and option arrays have compatible shapes [OK]

Common Mistakes:

• Assuming index values cause error
• Thinking np.choose needs boolean index
• Believing np.choose limits number of options

5. You have three arrays representing scores from three different tests:

test1 = np.array([80, 90, 70])
test2 = np.array([85, 88, 75])
test3 = np.array([78, 92, 72])

And an index array indicating the best test for each student:

best = np.array([1, 2, 0])

Using np.choose(), how do you create an array of the best scores for each student?

hard

A. np.choose(best, [test1, test3, test2])

B. np.choose(best, [test3, test1, test2])

C. np.choose(best, [test2, test3, test1])

D. np.choose(best, [test1, test2, test3])

Solution

1. Step 1: Understand index array meaning

   Index array best = [1, 2, 0] means:
   For student 0, best test is index 1 -> test2
   For student 1, best test is index 2 -> test3
   For student 2, best test is index 0 -> test1

2. Step 2: Match option arrays order to index

   To pick correctly, option arrays must be in order [test1, test2, test3] so index 0 picks test1, index 1 picks test2, index 2 picks test3.

3. Step 3: Verify np.choose usage

   Using np.choose(best, [test1, test2, test3]) picks correct scores per student.

4. Final Answer:

   np.choose(best, [test1, test2, test3]) -> Option D

5. Quick Check:

   Order options to match index meaning [OK]

Hint: Order option arrays to match index values [OK]

Common Mistakes:

• Assuming option arrays order matches test numbers
• Not matching index values to option array order
• Using wrong order causing incorrect selection