np.broadcast_to() for explicit broadcasting in NumPy - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does np.broadcast_to() do in NumPy?

np.broadcast_to() takes a smaller array and "stretches" it to a larger shape without copying data. It allows you to explicitly broadcast an array to a new shape.

beginner

Why is broadcasting useful in data science?

Broadcasting lets you perform operations on arrays of different shapes easily, like adding a single value to every element in a matrix, without writing loops.

intermediate

What happens if you try to broadcast to an incompatible shape with np.broadcast_to()?

NumPy will raise a ValueError because the shapes cannot be matched according to broadcasting rules.

beginner

Example: What is the output shape of np.broadcast_to(np.array([1, 2, 3]), (3, 3))?

The output shape is (3, 3). The 1D array [1, 2, 3] is broadcasted to 3 rows, repeating the original array in each row.

intermediate

Does np.broadcast_to() copy data or create a view?

It creates a view with broadcasted shape, so no new data is copied. This is memory efficient.

What is the main purpose of np.broadcast_to()?

A To sort an array

B To reshape an array by changing its data

C To copy an array multiple times

D To explicitly broadcast an array to a new shape

np.broadcast_to() explicitly broadcasts an array to a new shape without copying data.

If you have arr = np.array([5]), what will np.broadcast_to(arr, (2,3)) produce?

A An error because shapes don't match

B (2,3) array filled with 5

C (1,) array with 5

D (3,2) array filled with 5

Scalar 5 is broadcasted to fill the (2,3) shape.

What error occurs if broadcasting shapes are incompatible?

A ValueError

B TypeError

C IndexError

D KeyError

NumPy raises a ValueError when shapes cannot be broadcasted.

Does np.broadcast_to() create a copy of the data?

A Yes, it copies data

B Only for 2D arrays

C No, it creates a view

D Only if the array is large

It creates a view with broadcasted shape, saving memory.

Which of these shapes can np.broadcast_to() broadcast arr.shape = (3,) to?

A (3, 3)

B (4, 4)

C (3, 4)

D (2, 2)

Shape (3,) can broadcast to (3, 3) by repeating along the new axis.

Explain how np.broadcast_to() helps when working with arrays of different shapes.

Think about how you can stretch a small array to match a bigger one without loops.

Describe a real-life example where you might use np.broadcast_to() in data analysis.

Imagine adding a tax rate to every price in a table.

Practice

1. What does np.broadcast_to() do in NumPy?

easy

A. It sorts the elements of an array in ascending order.

B. It removes duplicate elements from an array.

C. It stretches an array to a larger shape without copying data.

D. It converts an array into a list.

Solution

1. Step 1: Understand the purpose of np.broadcast_to()

   This function is used to stretch an array to a bigger shape so it can be used in element-wise operations with other arrays.

2. Step 2: Compare with other options

   Sorting, removing duplicates, or converting to list are unrelated to broadcasting.

3. Final Answer:

   It stretches an array to a larger shape without copying data. -> Option C

4. Quick Check:

   Broadcasting = Stretch array shape [OK]

Hint: Broadcasting means stretching shape, not sorting or converting [OK]

Common Mistakes:

• Confusing broadcasting with sorting or reshaping
• Thinking it copies data instead of reusing
• Mixing it up with array conversion functions

2. Which of the following is the correct syntax to broadcast array a to shape (3, 4)?

easy

A. np.broadcast_to(a, (3, 4))

B. np.broadcast(a, shape=(3, 4))

C. np.broadcast_to(a, shape=3, 4)

D. np.broadcast(a, (3, 4))

Solution

1. Step 1: Recall the function signature

   The correct function is np.broadcast_to(array, shape) where shape is a tuple.

2. Step 2: Check each option

   np.broadcast_to(a, (3, 4)) matches the correct syntax. np.broadcast_to(a, shape=3, 4) incorrectly uses shape=3, 4 without tuple (int shape invalid). Options B and D use a non-existent np.broadcast function.

3. Final Answer:

   np.broadcast_to(a, (3, 4)) -> Option A

4. Quick Check:

   Correct syntax = np.broadcast_to(array, shape) [OK]

Hint: Use np.broadcast_to(array, shape) with shape as tuple [OK]

Common Mistakes:

• Using np.broadcast instead of np.broadcast_to
• Forgetting tuple around shape like shape=3, 4
• Confusing function names

3. What is the output of this code?

import numpy as np
x = np.array([1, 2, 3])
y = np.broadcast_to(x, (3, 3))
print(y)

medium

A. Error: shapes not compatible

B. [[1 1 1]
[2 2 2]
[3 3 3]]

C. [1 2 3 1 2 3 1 2 3]

D. [[1 2 3]
[1 2 3]
[1 2 3]]

Solution

1. Step 1: Understand the input array and target shape

   The array x is 1D with shape (3,). Broadcasting it to (3, 3) repeats it along the new axis.

2. Step 2: Visualize the broadcasted array

   The array x is repeated 3 times as rows, so the output is a 3x3 array with each row [1 2 3].

3. Final Answer:

   [[1 2 3] [1 2 3] [1 2 3]] -> Option D

4. Quick Check:

   Broadcast repeats rows = [[1 2 3], [1 2 3], [1 2 3]] [OK]

Hint: Broadcast 1D array to 2D repeats rows [OK]

Common Mistakes:

• Thinking broadcasting repeats columns instead of rows
• Expecting a flattened array
• Assuming an error due to shape mismatch

4. What is wrong with this code?

import numpy as np
arr = np.array([1, 2])
result = np.broadcast_to(arr, (3, 3))
print(result)

medium

A. ValueError because shape (3, 3) is incompatible with input shape (2,).

B. SyntaxError due to missing parentheses.

C. TypeError because broadcast_to expects a list, not an array.

D. No error; output is a 3x3 array with repeated rows.

Solution

1. Step 1: Check input and target shapes

   The input array has shape (2,), but the target shape is (3, 3). Broadcasting requires the input shape to be compatible with the target shape.

2. Step 2: Understand broadcasting rules

   Since 2 does not match 3 in the last dimension, broadcasting cannot stretch (2,) to (3, 3). This causes a ValueError.

3. Final Answer:

   ValueError because shape (3, 3) is incompatible with input shape (2,). -> Option A

4. Quick Check:

   Shape mismatch causes ValueError [OK]

Hint: Broadcast shapes must be compatible; check dimensions carefully [OK]

Common Mistakes:

• Assuming broadcasting always works regardless of shape
• Confusing ValueError with TypeError
• Ignoring dimension mismatch

5. You have a 1D array a = np.array([5]) and want to create a 3x4 array where every element is 5 using np.broadcast_to(). Which code correctly achieves this?

hard

A. np.broadcast_to(a, (4, 3))

B. np.broadcast_to(a, (3, 4))

C. np.broadcast_to(a, (3,))

D. np.broadcast_to(a, (5, 5))

Solution

1. Step 1: Identify the input and desired output shape

   The input is a 1D array with shape (1,), and the desired output shape is (3, 4).

2. Step 2: Apply broadcasting rules

   Broadcasting can stretch (1,) to (3, 4) by repeating the single value 5 across all elements.

3. Step 3: Check options

   np.broadcast_to(a, (3, 4)) correctly uses np.broadcast_to(a, (3, 4)). np.broadcast_to(a, (4, 3)) swaps dimensions, which is not the requested shape. np.broadcast_to(a, (3,)) is only 1D, and np.broadcast_to(a, (5, 5)) has wrong shape.

4. Final Answer:

   np.broadcast_to(a, (3, 4)) -> Option B

5. Quick Check:

   Broadcast single value to (3,4) with np.broadcast_to [OK]

Hint: Broadcast single-element array to target shape tuple [OK]

Common Mistakes:

• Mixing up shape dimensions order
• Using wrong target shape tuple
• Trying to broadcast to incompatible shapes