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Random choice from array in NumPy - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to select a random element from the array using NumPy.

NumPy
import numpy as np
arr = np.array([10, 20, 30, 40, 50])
random_element = np.random.[1](arr)
print(random_element)
Drag options to blanks, or click blank then click option'
Ashuffle
Bchoice
Crandint
Drandom
Attempts:
3 left
💡 Hint
Common Mistakes
Using np.random.randint which returns a random integer, not an element from the array.
Using np.random.shuffle which shuffles the array instead of selecting one element.
2fill in blank
medium

Complete the code to select 3 random elements from the array with replacement.

NumPy
import numpy as np
arr = np.array([5, 10, 15, 20, 25])
sample = np.random.choice(arr, size=[1], replace=True)
print(sample)
Drag options to blanks, or click blank then click option'
A1
B5
C3
D10
Attempts:
3 left
💡 Hint
Common Mistakes
Setting size to 1 or 5 which does not match the requirement.
Forgetting to set replace=True when sampling with replacement.
3fill in blank
hard

Fix the error in the code to select 2 unique random elements from the array.

NumPy
import numpy as np
arr = np.array([1, 2, 3, 4, 5])
sample = np.random.choice(arr, size=[1], replace=False)
print(sample)
Drag options to blanks, or click blank then click option'
A2
B3
C4
D1
Attempts:
3 left
💡 Hint
Common Mistakes
Using replace=True which allows duplicates.
Setting size to 1 or more than 2 which does not match the requirement.
4fill in blank
hard

Fill both blanks to create a dictionary with elements as keys and their squares as values for elements greater than 3.

NumPy
import numpy as np
arr = np.array([1, 2, 3, 4, 5])
squares = {x: x[1]2 for x in arr if x [2] 3}
print(squares)
Drag options to blanks, or click blank then click option'
A**
B%
C>
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using % instead of ** for power.
Using < instead of > for filtering.
5fill in blank
hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than 10.

NumPy
data = {'a': 5, 'b': 15, 'c': 20}
result = [1]: [2] for [3], [2] in data.items() if [2] > 10
print(result)
Drag options to blanks, or click blank then click option'
Ak.upper()
Bv
Ck
Ditem
Attempts:
3 left
💡 Hint
Common Mistakes
Using item as loop variable instead of k.
Not converting keys to uppercase.
Using wrong variable names for keys or values.

Practice

(1/5)
1.

What does the numpy.random.choice function do?

easy
A. It picks one or more random elements from an array.
B. It sorts the array in ascending order.
C. It calculates the mean of the array elements.
D. It removes duplicate elements from the array.

Solution

  1. Step 1: Understand the function purpose

    numpy.random.choice is used to select random elements from an array.
  2. Step 2: Compare with other options

    Sorting, calculating mean, or removing duplicates are different functions and unrelated to random choice.
  3. Final Answer:

    It picks one or more random elements from an array. -> Option A
  4. Quick Check:

    Random choice = pick random elements [OK]
Hint: Random choice picks elements randomly from an array [OK]
Common Mistakes:
  • Confusing random choice with sorting
  • Thinking it calculates statistics like mean
  • Assuming it removes duplicates
2.

Which of the following is the correct syntax to pick 3 random elements from a numpy array arr with replacement?

import numpy as np
arr = np.array([10, 20, 30, 40, 50])
easy
A. np.random.choice(arr, size=3, replace=False)
B. np.random.choice(arr, 3, replace=False)
C. np.random.choice(arr, size=3, replace=True)
D. np.random.choice(arr, 3, replace=True, axis=1)

Solution

  1. Step 1: Check correct parameter names

    The function uses size to specify number of elements and replace to allow repeats.
  2. Step 2: Validate each option

    np.random.choice(arr, size=3, replace=True) uses correct parameters: size=3 and replace=True. Others have wrong parameter names or extra invalid ones.
  3. Final Answer:

    np.random.choice(arr, size=3, replace=True) -> Option C
  4. Quick Check:

    Correct syntax = size=3, replace=True [OK]
Hint: Use size= and replace= parameters correctly [OK]
Common Mistakes:
  • Using positional argument without size=
  • Setting replace=False when repeats are needed
  • Adding invalid parameters like axis
3.

What is the output of this code?

import numpy as np
np.random.seed(0)
arr = np.array([1, 2, 3, 4, 5])
result = np.random.choice(arr, size=4, replace=False)
print(result)
medium
A. [5 1 4 3]
B. [4 5 1 3]
C. [1 2 3 4]
D. [2 5 1 4]

Solution

  1. Step 1: Understand seed and choice without replacement

    Setting seed ensures reproducible random results. Choosing 4 unique elements without replacement picks 4 different values from arr.
  2. Step 2: Run code or recall output

    With seed 0, the output is [2 5 1 4].
  3. Final Answer:

    [2 5 1 4] -> Option D
  4. Quick Check:

    Seed 0 + replace=False = [2 5 1 4] [OK]
Hint: Use np.random.seed for consistent random output [OK]
Common Mistakes:
  • Ignoring seed and expecting different output
  • Confusing replace=True and replace=False results
  • Assuming output is sorted
4.

Identify the error in this code snippet:

import numpy as np
arr = np.array([1, 2, 3])
result = np.random.choice(arr, size=5, replace=False)
print(result)
medium
A. Size is larger than array length without replacement, causing an error.
B. Array is not defined properly.
C. Missing import statement for numpy.
D. replace parameter should be True to avoid error.

Solution

  1. Step 1: Check size vs array length with replace=False

    Choosing 5 elements without replacement from an array of length 3 is invalid and raises an error.
  2. Step 2: Confirm other parts are correct

    Array is defined, numpy is imported, and replace parameter is valid. The main issue is size too large without replacement.
  3. Final Answer:

    Size is larger than array length without replacement, causing an error. -> Option A
  4. Quick Check:

    Size > array length + replace=False = error [OK]
Hint: Size must not exceed array length if replace=False [OK]
Common Mistakes:
  • Ignoring size vs array length mismatch
  • Assuming replace=True by default
  • Not importing numpy before use
5.

You have a numpy array data = np.array([10, 20, 30, 40, 50]). You want to randomly select 3 unique elements but ensure the number 20 is always included in the result. Which approach is correct?

hard
A. Pick 3 elements with replacement and filter for 20 after.
B. Remove 20 from array, pick 2 without replacement, then add 20 back.
C. Use np.random.choice(data, size=3, replace=False) directly.
D. Pick 3 elements with replacement and add 20 manually.

Solution

  1. Step 1: Understand the requirement

    We want 3 unique elements including 20 always.
  2. Step 2: Choose method to guarantee 20

    Remove 20, pick 2 unique elements from remaining, then add 20 to result ensures 20 is included and no duplicates.
  3. Step 3: Evaluate other options

    Direct random choice may exclude 20. Picking with replacement can cause duplicates or exclude 20. Adding 20 manually after picking with replacement may cause duplicates.
  4. Final Answer:

    Remove 20 from array, pick 2 without replacement, then add 20 back. -> Option B
  5. Quick Check:

    Guarantee element by picking rest then adding it [OK]
Hint: Pick others without 20, then add 20 to ensure inclusion [OK]
Common Mistakes:
  • Assuming random choice always includes 20
  • Using replacement causing duplicates
  • Adding 20 after picking with replacement causing repeats