np.random.default_rng() modern approach in NumPy - Mini Project: Build & Apply

Using np.random.default_rng() to Generate Random Numbers

📖 Scenario: Imagine you are a data scientist who needs to generate random numbers for a simulation. Using the modern np.random.default_rng() method helps you create random numbers in a simple and reliable way.

🎯 Goal: You will create a random number generator, set a seed for reproducibility, generate a list of random integers, and then print the list.

📋 What You'll Learn

Create a random number generator using np.random.default_rng()

Set the seed to 123 for reproducibility

Generate 5 random integers between 10 and 50 (inclusive)

Print the list of generated random integers

💡 Why This Matters

🌍 Real World

Random number generation is used in simulations, games, and testing to create unpredictable but reproducible data.

💼 Career

Data scientists and analysts use random number generators to create sample data, run simulations, and test models.

1

Create a random number generator

Import numpy as np and create a random number generator called rng using np.random.default_rng().

NumPy

import numpy as np
# Create a random number generator called rng
# Your code here

Hint

Use rng = np.random.default_rng() to create the generator.

2

Set the seed for reproducibility

Create a random number generator called rng with the seed 123 using np.random.default_rng(123).

NumPy

import numpy as np
# Create rng with seed 123
# Your code here

Hint

Pass the seed 123 as an argument to default_rng().

3

Generate 5 random integers between 10 and 50

Use the rng.integers() method to generate 5 random integers between 10 (inclusive) and 51 (exclusive) and store them in a variable called random_numbers.

NumPy

import numpy as np
rng = np.random.default_rng(123)
# Generate 5 random integers between 10 and 50
# Your code here

Hint

Use rng.integers(10, 51, size=5) to get 5 integers from 10 to 50.

4

Print the list of random integers

Print the variable random_numbers to display the generated random integers.

NumPy

import numpy as np
rng = np.random.default_rng(123)
random_numbers = rng.integers(10, 51, size=5)
# Print the random_numbers
# Your code here

Hint

Use print(random_numbers) to show the numbers.

Practice

1. What does np.random.default_rng() do in NumPy?

easy

A. Creates a modern random number generator instance

B. Generates a fixed list of numbers

C. Imports the NumPy library

D. Sorts an array in ascending order

Solution

1. Step 1: Understand the function purpose

   np.random.default_rng() creates a new random number generator object using the modern Generator API.

2. Step 2: Compare with other options

   It does not generate fixed lists, import libraries, or sort arrays.

3. Final Answer:

   Creates a modern random number generator instance -> Option A

4. Quick Check:

   default_rng() = modern RNG instance [OK]

Hint: Remember default_rng() always creates a new RNG object [OK]

Common Mistakes:

• Confusing it with random number generation output
• Thinking it imports NumPy
• Mixing it up with sorting functions

2. Which of the following is the correct way to create a random number generator with a seed of 42 using np.random.default_rng()?

easy

A. rng = np.random.default_rng(42, seed=42)

B. rng = np.random.default_rng(42)

C. rng = np.random.default_rng().seed(42)

D. rng = np.random.default_rng().random(42)

Solution

1. Step 1: Check the correct syntax for seeding

   The seed is passed as an argument directly to default_rng(), so np.random.default_rng(42) is correct.

2. Step 2: Evaluate other options

   rng = np.random.default_rng(42, seed=42) is invalid because it passes seed both positionally and as keyword, causing TypeError: multiple values for 'seed'. rng = np.random.default_rng().seed(42) tries to call seed() method which does not exist on the Generator. rng = np.random.default_rng().random(42) calls random(42) which generates numbers, not seeds.

3. Final Answer:

   rng = np.random.default_rng(42) -> Option B

4. Quick Check:

   Seed passed as argument = rng = np.random.default_rng(42) [OK]

Hint: Pass seed directly inside default_rng() parentheses [OK]

Common Mistakes:

• Passing seed both positionally and as keyword argument
• Calling seed() method on the generator
• Confusing random() method with seeding

3. What is the output of this code?

import numpy as np
rng = np.random.default_rng(123)
print(rng.integers(1, 10, size=3))

medium

A. [3 3 7]

B. [3 1 7]

C. [2 3 7]

D. [3 3 6]

Solution

1. Step 1: Understand the code

   The code creates a random number generator with seed 123, then generates 3 random integers between 1 (inclusive) and 10 (exclusive).

2. Step 2: Run the code or recall output

   Running this code produces the array [3 3 7].

3. Final Answer:

   [3 3 7] -> Option A

4. Quick Check:

   Seed 123 + integers(1,10,3) = [3 3 7] [OK]

Hint: Seed fixes output; integers(1,10,3) gives same 3 numbers [OK]

Common Mistakes:

• Assuming inclusive upper bound 10
• Confusing seed effect on output
• Mixing output with floats instead of integers

4. Identify the error in this code snippet:

import numpy as np
rng = np.random.default_rng()
random_numbers = rng.random(5, seed=10)
print(random_numbers)

medium

A. random() should be called without parentheses

B. default_rng() requires a seed argument

C. random() does not accept a seed argument

D. rng.random() returns integers, not floats

Solution

1. Step 1: Check method signature of random()

   The random() method of the Generator does not accept a seed parameter; seeding is done when creating the generator.

2. Step 2: Identify the error

   Passing seed=10 to random() causes a TypeError.

3. Final Answer:

   random() does not accept a seed argument -> Option C

4. Quick Check:

   Seed only in default_rng(), not in random() [OK]

Hint: Seed only when creating RNG, not in random() calls [OK]

Common Mistakes:

• Trying to seed random() method
• Thinking random() returns integers
• Believing default_rng() needs seed always

5. You want to generate a reproducible shuffled version of the list [10, 20, 30, 40, 50] using np.random.default_rng(). Which code correctly achieves this?

hard

A. rng = np.random.default_rng(7)
arr = [10, 20, 30, 40, 50]
rng.shuffle(arr)
print(arr)

B. rng = np.random.default_rng()
arr = [10, 20, 30, 40, 50]
rng.shuffle(arr)
print(arr)

C. rng = np.random.default_rng(7)
arr = [10, 20, 30, 40, 50]
shuffled = np.random.shuffle(arr)
print(shuffled)

D. rng = np.random.default_rng(7)
arr = [10, 20, 30, 40, 50]
shuffled = rng.permutation(arr)
print(shuffled)

Solution

1. Step 1: Understand reproducible shuffling

   To get reproducible shuffling, seed the generator and use its methods. rng.shuffle() shuffles in-place and returns None, while rng.permutation() returns a shuffled copy.

2. Step 2: Analyze options

   rng = np.random.default_rng(7) arr = [10, 20, 30, 40, 50] rng.shuffle(arr) print(arr) fails because rng.shuffle() requires a NumPy ndarray but arr is a list (TypeError). rng = np.random.default_rng() arr = [10, 20, 30, 40, 50] rng.shuffle(arr) print(arr) has no seed, so not reproducible (also fails on list). rng = np.random.default_rng(7) arr = [10, 20, 30, 40, 50] shuffled = np.random.shuffle(arr) print(shuffled) incorrectly uses np.random.shuffle() which ignores rng, requires ndarray (fails on list), and returns None. rng = np.random.default_rng(7) arr = [10, 20, 30, 40, 50] shuffled = rng.permutation(arr) print(shuffled) seeds and uses permutation() to get a reproducible shuffled copy.

3. Final Answer:

   rng = np.random.default_rng(7) arr = [10, 20, 30, 40, 50] shuffled = rng.permutation(arr) print(shuffled) -> Option D

4. Quick Check:

   Seed + permutation() = reproducible shuffled copy [OK]

Hint: Use rng.permutation(arr) with seed for reproducible shuffle [OK]

Common Mistakes:

• Using np.random.shuffle() ignoring seed
• Expecting shuffle() to return a new list
• Not seeding the generator for reproducibility