np.power() and np.square() in NumPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to square each element in the array using np.square().

NumPy

import numpy as np
arr = np.array([1, 2, 3, 4])
squared = np.[1](arr)
print(squared)

Drag options to blanks, or click blank then click option'

Aabs

Bpower

Csqrt

Dsquare

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.sqrt() which computes the square root instead.

Using np.abs() which computes absolute values.

np.square() computes the square of each element in the array.

2fill in blank

medium

Complete the code to raise each element in the array to the power of 3 using np.power().

NumPy

import numpy as np
arr = np.array([1, 2, 3, 4])
cubed = np.power(arr, [1])
print(cubed)

Drag options to blanks, or click blank then click option'

A3

B4

C2

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using 2 which squares instead of cubes.

Using 0 which results in all ones.

np.power(arr, 3) raises each element of arr to the power of 3 (cube).

3fill in blank

hard

Fix the error in the code to correctly square the array elements using np.power().

NumPy

import numpy as np
arr = np.array([2, 3, 4])
squared = np.power(arr, [1])
print(squared)

Drag options to blanks, or click blank then click option'

A1

Barr

C2

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using 1 which returns the original array.

Using 0 which returns ones.

The second argument to np.power() is the exponent. To square, use 2.

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their squared lengths as values, only for words longer than 3 characters.

NumPy

import numpy as np
words = ['data', 'science', 'ai', 'ml']
squared_lengths = {word: [1] for word in words if len(word) [2] 3}
print(squared_lengths)

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Anp.square(len(word))

Bnp.power(len(word), 3)

C>

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.power(len(word), 3) which cubes instead of squares.

Using <= which selects shorter words.

We square the length using np.square(len(word)) and filter words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys and their squared lengths as values, only for words longer than 2 characters.

NumPy

import numpy as np
words = ['cat', 'dog', 'a', 'elephant']
squared_lengths = { [1]: [2] for word in words if len(word) [3] 2}
print(squared_lengths)

Drag options to blanks, or click blank then click option'

Aword.upper()

Bnp.square(len(word))

C>

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lower() instead of upper().

Using < instead of > for filtering.

Using len(word) without np.square().

Keys are uppercase words using word.upper(), values are squared lengths using np.square(len(word)), and filter words longer than 2 using >.