np.any() and np.all() in NumPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if any element in the array is True.

NumPy

import numpy as np
arr = np.array([False, False, True, False])
result = np.[1](arr)
print(result)

Drag options to blanks, or click blank then click option'

Aall

Bsum

Cany

Dmean

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.all() which checks if all elements are True.

Using sum() or mean() which return numeric values, not boolean.

The np.any() function returns True if at least one element in the array is True.

2fill in blank

medium

Complete the code to check if all elements in the array are True.

NumPy

import numpy as np
arr = np.array([True, True, True])
result = np.[1](arr)
print(result)

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Aall

Bany

Cmax

Dmin

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.any() which returns True if any element is True.

Using max() or min() which return numeric values.

The np.all() function returns True only if every element in the array is True.

3fill in blank

hard

Fix the error in the code to correctly check if any element is True along axis 0.

NumPy

import numpy as np
arr = np.array([[False, True], [False, False]])
result = np.any(arr, axis=[1])
print(result)

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A0

B2

C-1

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using axis=1 which checks rows instead of columns.

Using axis=2 which is invalid for 2D arrays.

Axis 0 means checking down the rows (columns). Using axis=0 checks each column for any True value.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if all characters are alphabetic.

NumPy

words = ['apple', 'banana', '123', 'pear']
lengths = {word: len(word) for word in words if word.[1]() and all(c.[2]() for c in word)}
print(lengths)

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Aisalpha

Bisdigit

Dislower

Attempts:

3 left

💡 Hint

Common Mistakes

Using isdigit() which checks for digits, not letters.

Using islower() which checks for lowercase but not alphabetic.

The isalpha() method checks if all characters in a string are letters. The comprehension filters words where word.isalpha() is True and all characters c.isalpha() are letters.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths only if any character is uppercase and all characters are alphabetic.

NumPy

words = ['Apple', 'BANANA', '123', 'Pear']
result = {word.[1](): len(word) for word in words if any(c.[2]() for c in word) and all(c.[3]() for c in word)}
print(result)

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Aupper

Bisupper

Cisalpha

Dlower

Attempts:

3 left

💡 Hint

Common Mistakes

Using lower() instead of upper() to convert words.

Using islower() or isdigit() instead of isupper() or isalpha().

The comprehension converts words to uppercase with word.upper(). It includes words where any character is uppercase (c.isupper()) and all characters are alphabetic (c.isalpha()).