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Recall & Review
beginner
What does the numpy.random.normal() function do?
It generates random numbers that follow a normal (bell-shaped) distribution, centered around a mean value with a given spread (standard deviation).
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beginner
What are the main parameters of numpy.random.normal()?
The main parameters are loc (mean), scale (standard deviation), and size (number of values to generate).
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beginner
Why is the standard deviation important in a normal distribution?
Standard deviation controls how spread out the numbers are around the mean. A small value means numbers are close to the mean; a large value means they are more spread out.
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beginner
How can you generate 1000 random numbers with mean 10 and standard deviation 2 using numpy?
Use numpy.random.normal(loc=10, scale=2, size=1000) to get 1000 numbers centered at 10 with spread 2.
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intermediate
What shape of data does numpy.random.normal() return when size is a tuple?
It returns a NumPy array with the shape given by the tuple, filled with random numbers from the normal distribution.
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What does the loc parameter in numpy.random.normal() specify?
AThe number of samples to generate
BThe mean of the distribution
CThe standard deviation of the distribution
DThe minimum value of the distribution
✗ Incorrect
loc sets the center (mean) of the normal distribution.
If you want to generate 500 random numbers from a normal distribution, which parameter controls this?
Aloc
Bscale
Csize
Dmean
✗ Incorrect
size controls how many random numbers are generated.
What happens if you set scale=0 in numpy.random.normal()?
AYou get random numbers spread out widely
BYou get negative numbers only
CYou get an error
DYou get all numbers equal to the mean
✗ Incorrect
With zero standard deviation, all values equal the mean.
Which shape will the output have if you use size=(3,4)?
AA 3 by 4 NumPy array
BA list of 12 numbers
CA single number
DA 4 by 3 NumPy array
✗ Incorrect
The output shape matches the size tuple, so 3 rows and 4 columns.
Which of these is true about the normal distribution?
AIt is symmetric around the mean
BIt has no mean
CIt only produces positive numbers
DIt is always skewed to the right
✗ Incorrect
The normal distribution is symmetric around its mean.
Explain how to use numpy.random.normal() to simulate real-world data like heights or test scores.
Think about how average and spread describe real data.
You got /5 concepts.
Describe the effect of changing the scale parameter on the shape of the data generated by numpy.random.normal().
Consider what happens when spread increases or decreases.
You got /4 concepts.
Practice
(1/5)
1. What does the loc parameter control in the numpy.random.normal() function?
easy
A. The spread (standard deviation) of the normal distribution
B. The center (mean) of the normal distribution
C. The number of random values generated
D. The shape of the distribution curve
Solution
Step 1: Understand the parameters of normal()
The normal() function has parameters loc and scale. loc sets the mean (center) of the distribution.
Step 2: Identify the role of loc
The mean is the center point where most values cluster in a bell curve.
Final Answer:
The center (mean) of the normal distribution -> Option B
Quick Check:
loc = center [OK]
Hint: Remember: loc = center, scale = spread [OK]
Common Mistakes:
Confusing loc with scale
Thinking loc controls number of samples
Assuming loc changes distribution shape
2. Which of the following is the correct syntax to generate 5 random numbers from a normal distribution with mean 10 and standard deviation 2 using numpy?
easy
A. numpy.random.normal(size=5, mean=10, std=2)
B. numpy.normal(10, 2, 5)
C. numpy.random.normal(5, loc=10, scale=2)
D. numpy.random.normal(loc=10, scale=2, size=5)
Solution
Step 1: Recall the correct function and parameters
The function is numpy.random.normal() with parameters loc for mean, scale for std dev, and size for number of samples.
Step 2: Match parameters to correct syntax
numpy.random.normal(loc=10, scale=2, size=5) correctly uses loc=10, scale=2, and size=5.
Final Answer:
numpy.random.normal(loc=10, scale=2, size=5) -> Option D
Quick Check:
Correct parameter names and order [OK]
Hint: Use loc=mean, scale=std, size=number [OK]
Common Mistakes:
Using wrong parameter names like mean or std
Mixing order without keywords
Calling numpy.normal instead of numpy.random.normal
3. What is the output shape of the following code?
import numpy as np
arr = np.random.normal(loc=0, scale=1, size=(3,4))
print(arr.shape)
medium
A. (12,)
B. (4, 3)
C. (3, 4)
D. (3,)
Solution
Step 1: Understand the size parameter
The size argument is set to (3,4), which means generate a 2D array with 3 rows and 4 columns.
Step 2: Check the shape of the generated array
Printing arr.shape returns the shape tuple, which matches the size argument.
Final Answer:
(3, 4) -> Option C
Quick Check:
size=(3,4) means shape=(3,4) [OK]
Hint: size tuple = output shape [OK]
Common Mistakes:
Confusing rows and columns order
Expecting flattened array shape
Ignoring tuple format for size
4. Identify the error in this code snippet:
import numpy as np
samples = np.random.normal(mean=0, std=1, size=10)
print(samples)
medium
A. Incorrect parameter names: should use loc and scale instead of mean and std
B. Missing import statement for numpy
C. size parameter must be a tuple, not an integer
D. The print statement syntax is wrong
Solution
Step 1: Check parameter names for normal()
The function np.random.normal() expects loc for mean and scale for standard deviation, not mean or std.
Step 2: Verify other parts of the code
Import is correct, size can be integer, and print syntax is valid.
Final Answer:
Incorrect parameter names: should use loc and scale instead of mean and std -> Option A
Quick Check:
Use loc and scale for mean and std [OK]
Hint: Use loc=mean, scale=std; mean/std are invalid [OK]
Common Mistakes:
Using mean or std instead of loc and scale
Thinking size must be tuple always
Assuming print syntax error
5. You want to simulate daily temperatures for a week that average 20°C with a standard deviation of 3°C. Which code correctly generates this data and calculates the average temperature?
hard
A. temps = np.random.normal(loc=20, scale=3, size=7)
avg_temp = temps.mean()
print(round(avg_temp, 2))
B. temps = np.random.normal(mean=20, std=3, size=7)
avg_temp = temps.sum()
print(avg_temp)
C. temps = np.random.normal(loc=3, scale=20, size=7)
avg_temp = temps.mean()
print(avg_temp)
D. temps = np.random.normal(loc=20, scale=3, size=7)
avg_temp = temps.median()
print(avg_temp)
Solution
Step 1: Generate temperatures with correct parameters
Use loc=20 for mean temperature and scale=3 for standard deviation, with size=7 for a week.
Step 2: Calculate the average temperature correctly
Use temps.mean() to get the average. Round for neat output.
Final Answer:
temps = np.random.normal(loc=20, scale=3, size=7)
avg_temp = temps.mean()
print(round(avg_temp, 2)) -> Option A
Quick Check:
loc=mean, scale=std, mean() for average [OK]
Hint: Use loc=mean, scale=std, mean() to average [OK]