Accessing fields by name in NumPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to access the 'age' field from the structured array.

NumPy

ages = data['[1]']

Drag options to blanks, or click blank then click option'

Aages

Bage

Cdata

Dname

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong field name.

Trying to access fields with dot notation instead of brackets.

To access a field by name in a structured NumPy array, use the field name as a string inside square brackets.

2fill in blank

medium

Complete the code to get the 'score' field from the structured array.

NumPy

scores = data['[1]']

Drag options to blanks, or click blank then click option'

Ascore

Bscores

Cvalue

DScore

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect capitalization.

Using plural form when the field is singular.

The field name is case-sensitive and must match exactly as defined in the structured array.

3fill in blank

hard

Fix the error in accessing the 'height' field from the structured array.

NumPy

heights = data[1]'height']

Drag options to blanks, or click blank then click option'

A[

B.

C('

D{

Attempts:

3 left

💡 Hint

Common Mistakes

Using dot notation instead of brackets.

Missing the opening bracket.

Fields in structured arrays are accessed using square brackets, not dot notation.

4fill in blank

hard

Fill both blanks to create a dictionary of names and ages from the structured array.

NumPy

result = {data['[1]'][i]: data['[2]'][i] for i in range(len(data))}

Drag options to blanks, or click blank then click option'

Aname

Bage

Cscore

Dheight

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping keys and values.

Using incorrect field names.

To create a dictionary mapping names to ages, use the 'name' field as keys and 'age' field as values.

5fill in blank

hard

Fill all three blanks to create a dictionary of uppercase names and their scores if the score is above 80.

NumPy

result = {data['[1]'][i].upper(): data['[2]'][i] for i in range(len(data)) if data['[3]'][i] > 80}

Drag options to blanks, or click blank then click option'

Aname

Bscore

Dage

Attempts:

3 left

💡 Hint

Common Mistakes

Using different fields for keys and values.

Not filtering scores correctly.

This dictionary comprehension uses the 'name' field converted to uppercase as keys, and the 'score' field as values, filtering only scores above 80.