[Solved] What is the output of the following code?import numpy as np print(np.eye(3, k=1)) — Ans: [[0. 1. 0.] [0. 0. 1.] [0. 0. 0.]] | NumPy

NumPy - Creating Arrays

What is the output of the following code?

import numpy as np
print(np.eye(3, k=1))

A[[0. 0. 1.] [0. 1. 0.] [1. 0. 0.]]

B[[1. 0. 0.] [0. 1. 0.] [0. 0. 1.]]

C[[0. 0. 0.] [1. 0. 0.] [0. 1. 0.]]

D[[0. 1. 0.] [0. 0. 1.] [0. 0. 0.]]

Step-by-Step Solution

Solution:

Step 1: Understand the k parameter in np.eye()
The parameter k=1 shifts the diagonal of 1s one above the main diagonal.
Step 2: Visualize the 3x3 matrix with 1s on the first upper diagonal
The 1s appear at positions (0,1) and (1,2), zeros elsewhere.
Final Answer:
[[0. 1. 0.] [0. 0. 1.] [0. 0. 0.]] -> Option D
Quick Check:
k=1 shifts diagonal up by 1 [OK]

Quick Trick: k shifts diagonal: 0=main, 1=above, -1=below [OK]

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