[Solved] What will be the output of this code?import numpy as np arr = np.array([5, 10, 15]) result = np.where(arr % 2 == 0, 'even', 'odd') print(result) | NumPy

NumPy - Indexing and Slicing

What will be the output of this code?

import numpy as np
arr = np.array([5, 10, 15])
result = np.where(arr % 2 == 0, 'even', 'odd')
print(result)

A['even' 'odd' 'even']

B['odd' 'odd' 'odd']

C[5 10 15]

D['odd' 'even' 'odd']

Step-by-Step Solution

Solution:

Step 1: Check condition arr % 2 == 0
Only 10 is even, 5 and 15 are odd.
Step 2: np.where assigns 'even' or 'odd'
Positions with True get 'even', others get 'odd'.
Final Answer:
['odd' 'even' 'odd'] -> Option D
Quick Check:
np.where(condition, 'even', 'odd') labels parity [OK]

Quick Trick: Use np.where for labeling based on condition [OK]

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