[Solved] Identify the error in this code snippet:import numpy as np x = np.array([1, 2, 3, 4]) y = np.array([10, 20, 30, 40]) result = np.where(x > 2, y) print(result) | NumPy

NumPy - Indexing and Slicing

Identify the error in this code snippet:

import numpy as np
x = np.array([1, 2, 3, 4])
y = np.array([10, 20, 30, 40])
result = np.where(x > 2, y)
print(result)

ACondition x > 2 is invalid syntax

BArrays x and y have different lengths

CMissing third argument for false condition in np.where()

Dnp.where() cannot be used with arrays

Step-by-Step Solution

Solution:

Step 1: Check np.where() arguments
np.where() requires three arguments for conditional selection: condition, array if True, array if False.
Step 2: Identify missing argument
The code only provides condition and one array, missing the third argument for false case.
Final Answer:
Missing third argument for false condition in np.where() -> Option C
Quick Check:
np.where needs condition, true array, false array [OK]

Quick Trick: np.where needs three arguments for selection [OK]

Common Mistakes:

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