[Solved] Consider this Node.js code snippet:setTimeout(() => console.log('timeout')... process.nextTick(() => console.log('another nextTick'));Which issue causes unexpected order of output, and how to fix it? | Node.js

Node.js - Timers and Scheduling

Consider this Node.js code snippet:

setTimeout(() => console.log('timeout'));
setImmediate(() => console.log('immediate'));
process.nextTick(() => console.log('nextTick'));
process.nextTick(() => console.log('another nextTick'));

Which issue causes unexpected order of output, and how to fix it?

Aprocess.nextTick callbacks run before setImmediate and setTimeout; no fix needed, it's expected.

BsetImmediate runs before process.nextTick; swap their calls to fix.

CMissing delay in setTimeout causes error; add delay 0 to fix.

DsetTimeout and setImmediate run simultaneously causing race; use only one.

Step-by-Step Solution

Solution:

Step 1: Analyze order of callbacks
process.nextTick callbacks always run before setImmediate and setTimeout, regardless of order in code.
Step 2: Understand if this is an issue
This behavior is by design in Node.js event loop; no error or fix needed.
Final Answer:
process.nextTick callbacks run before setImmediate and setTimeout; no fix needed, it's expected. -> Option A
Quick Check:
nextTick always runs first [OK]

Quick Trick: nextTick always runs before timers and immediate [OK]

Common Mistakes:

Thinking missing delay in setTimeout causes error
Expecting setImmediate to run before nextTick
Trying to fix timing by swapping calls

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More Node.js Quizzes

Consider this Node.js code snippet:

Step 1: Analyze order of callbacks

Step 2: Understand if this is an issue

Final Answer:

Quick Check:

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