[Solved] You want to run two async functions in parallel and handle errors separately. Which pattern is best?async function runTasks() { // Which code below correctly handles errors for both tasks? } | Node.js

Node.js - Error Handling Patterns

You want to run two async functions in parallel and handle errors separately. Which pattern is best?

async function runTasks() {
  // Which code below correctly handles errors for both tasks?
}

Aconst [res1, res2] = await Promise.all([task1(), task2()]);

Bconst res1 = await task1().catch(e => console.error('Task1 error', e)); const res2 = await task2().catch(e => console.error('Task2 error', e));

Ctry { await task1(); await task2(); } catch (e) { console.error(e); }

Dtask1().then().catch(); task2().then().catch();

Step-by-Step Solution

Solution:

Step 1: Understand parallel execution with error handling
Running tasks in parallel and handling errors separately requires catching errors individually.
Step 2: Evaluate options
const res1 = await task1().catch(e => console.error('Task1 error', e)); const res2 = await task2().catch(e => console.error('Task2 error', e)); awaits each task with its own catch, allowing separate error handling; others either combine errors or lack awaits.
Final Answer:
const res1 = await task1().catch(e => console.error('Task1 error', e)); const res2 = await task2().catch(e => console.error('Task2 error', e)); -> Option B
Quick Check:
Parallel with separate error handling = B [OK]

Quick Trick: Use individual catch on awaited promises for separate error handling [OK]

Common Mistakes:

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