[Solved] What will be the output order of the following Node.js code?console.log('start'); setTimeout(() => console.log('timeout'), 0); setImmediate(() => console.log('immediate')); process.... | Node.js

Node.js - Timers and Scheduling

What will be the output order of the following Node.js code?

console.log('start');
setTimeout(() => console.log('timeout'), 0);
setImmediate(() => console.log('immediate'));
process.nextTick(() => console.log('nextTick'));
console.log('end');

Astart, end, nextTick, timeout, immediate

Bstart, end, timeout, nextTick, immediate

Cstart, nextTick, end, immediate, timeout

Dstart, end, nextTick, immediate, timeout

Step-by-Step Solution

Solution:

Step 1: Identify synchronous and asynchronous parts
console.log('start') and console.log('end') run immediately. process.nextTick runs after current operation but before event loop phases.
Step 2: Understand event loop order
process.nextTick runs first, then setImmediate callbacks, then setTimeout with 0 delay.
Final Answer:
start, end, nextTick, immediate, timeout -> Option D
Quick Check:
nextTick before immediate before timeout [OK]

Quick Trick: nextTick runs before immediate and timeout [OK]

Common Mistakes:

Assuming setTimeout runs before setImmediate
Thinking nextTick runs after synchronous logs
Mixing order of immediate and timeout

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What will be the output order of the following Node.js code?

Step 1: Identify synchronous and asynchronous parts

Step 2: Understand event loop order

Final Answer:

Quick Check:

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