You spawn a child process in Node.js that may exit with code 7 or be terminated by a signal. Which code snippet correctly logs the exit code or the signal name?

hard📝 Application Q8 of 15

Node.js - Child Processes

const { spawn } = require('child_process');
const child = spawn('node', ['-e', 'process.exit(7)']);
child.on('exit', (code, signal) => {
  // What to log?
});

Achild.on('exit', (code, signal) => { console.log(signal || code); });

Bchild.on('exit', (code, signal) => { console.log(code || signal); });

Cchild.on('exit', (code) => { console.log(code); });

Dchild.on('exit', (signal) => { console.log(signal); });

Step-by-Step Solution

Solution:

Step 1: Understand exit event parameters
The 'exit' event provides code (number) and signal (string or null).
Step 2: Determine which to log
If the process was terminated by a signal, signal is non-null; otherwise, code holds the exit code.
Step 3: Correct logging logic
Logging signal || code ensures signal name is logged if present, else exit code.
Final Answer:
Option A correctly logs the signal or exit code. -> Option A
Quick Check:
Signal takes precedence over exit code [OK]

Quick Trick: Log signal if present, else exit code [OK]

Common Mistakes:

Logging code before checking signal
Ignoring signal parameter
Using only one parameter in listener

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More Node.js Quizzes

You spawn a child process in Node.js that may exit with code 7 or be terminated by a signal. Which code snippet correctly logs the exit code or the signal name?

Step 1: Understand exit event parameters

Step 2: Determine which to log

Step 3: Correct logging logic

Final Answer:

Quick Check:

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