[Solved] Why does this code never log the exit code?const { spawn } = require('child_process'); const child = spawn('node', ['-e', 'process.exit(3)']); child.on('exit', () => console.log('Exited')); | Node.js

Node.js - Child Processes

Why does this code never log the exit code?

const { spawn } = require('child_process');
const child = spawn('node', ['-e', 'process.exit(3)']);
child.on('exit', () => console.log('Exited'));

AThe exit event callback does not receive the exit code parameter

BThe child process never exits

CThe exit event is not emitted for process.exit()

DThe callback ignores the exit code parameter

Step-by-Step Solution

Solution:

Step 1: Check the exit event callback signature
The exit event callback receives the exit code as the first argument.
Step 2: Identify missing parameter usage
The callback does not declare a parameter, so the exit code is not logged.
Final Answer:
The callback ignores the exit code parameter -> Option D
Quick Check:
Declare parameter to access exit code [OK]

Quick Trick: Declare parameter in exit callback to get code [OK]

Common Mistakes:

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Why does this code never log the exit code?