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No-Codeknowledge~30 mins

Many-to-many relationships in No-Code - Mini Project: Build & Apply

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Understanding Many-to-Many Relationships
📖 Scenario: You are organizing a community event where people can join multiple clubs, and each club can have multiple members. You want to keep track of which people belong to which clubs.
🎯 Goal: Create a simple data structure that shows the many-to-many relationship between people and clubs.
📋 What You'll Learn
Create a list of people with exact names
Create a list of clubs with exact names
Create a dictionary that links each person to the clubs they belong to
Create a dictionary that links each club to the people who are members
💡 Why This Matters
🌍 Real World
Many-to-many relationships appear in social networks, school courses, event planning, and more where multiple entities connect in complex ways.
💼 Career
Understanding these relationships is important for database design, software development, and data organization in many jobs.
Progress0 / 4 steps
1
Create the list of people
Create a list called people with these exact names: 'Alice', 'Bob', and 'Charlie'.
No-Code
Need a hint?

Use square brackets to create a list and put the names inside quotes separated by commas.

2
Create the list of clubs
Create a list called clubs with these exact names: 'Chess', 'Book', and 'Cooking'.
No-Code
Need a hint?

Use a list like in step 1 but with the club names.

3
Link people to their clubs
Create a dictionary called person_to_clubs that links each person to the clubs they belong to with these exact entries: 'Alice' belongs to 'Chess' and 'Book', 'Bob' belongs to 'Book' and 'Cooking', and 'Charlie' belongs to 'Chess'.
No-Code
Need a hint?

Use curly braces to create a dictionary. Each key is a person, and the value is a list of clubs.

4
Link clubs to their members
Create a dictionary called club_to_people that links each club to the people who are members with these exact entries: 'Chess' has 'Alice' and 'Charlie', 'Book' has 'Alice' and 'Bob', and 'Cooking' has 'Bob'.
No-Code
Need a hint?

Use a dictionary where each key is a club and the value is a list of people.