Document similarity ranking in NLP - Practice Problems & Coding Challenges

Challenge - 5 Problems

🧠 Conceptual

intermediate

What does cosine similarity measure in document ranking?

Imagine you have two documents represented as vectors. What does cosine similarity tell you about these documents?

A The angle between the two document vectors, indicating how similar their content is.

B The total number of common words between the two documents.

C The difference in length between the two documents measured by word count.

D The sum of the frequencies of all words in both documents.

💡 Hint

Think about how vectors relate to each other in space.

Cosine similarity measures the cosine of the angle between two vectors. A smaller angle means the documents are more similar in content.

❓ Predict Output

intermediate

Output of cosine similarity calculation

What is the output of this Python code that calculates cosine similarity between two document vectors?

NLP

import numpy as np

doc1 = np.array([1, 2, 3])
doc2 = np.array([4, 5, 6])

cos_sim = np.dot(doc1, doc2) / (np.linalg.norm(doc1) * np.linalg.norm(doc2))
print(round(cos_sim, 2))

A 0.75

B 1.00

C 0.97

D 0.87

💡 Hint

Calculate dot product and norms carefully.

The cosine similarity between [1,2,3] and [4,5,6] is approximately 0.97 after rounding.

❓ Model Choice

advanced

Best model for semantic document similarity

You want to rank documents by meaning, not just word overlap. Which model is best for this?

A Bag-of-words model with Euclidean distance

B Count vectorizer with Jaccard similarity

C TF-IDF vectorizer with cosine similarity

D Pretrained transformer embeddings with cosine similarity

💡 Hint

Consider models that understand context and meaning.

Pretrained transformer embeddings capture semantic meaning better than simple count or TF-IDF models.

❓ Hyperparameter

advanced

Effect of embedding dimension on similarity ranking

How does increasing the embedding vector size affect document similarity ranking?

A It can improve accuracy but may cause overfitting or slow computation.

B It reduces accuracy because larger vectors are harder to compare.

C It has no effect on similarity ranking performance.

D It always improves ranking accuracy by capturing more details.

💡 Hint

Think about trade-offs between detail and complexity.

Larger embeddings can capture more information but may overfit or slow down similarity calculations.

❓ Metrics

expert

Choosing the best metric for ranking evaluation

You have a list of documents ranked by similarity to a query. Which metric best measures how well the ranking matches user relevance?

A Mean Squared Error (MSE)

B Precision at K (P@K)

C Root Mean Squared Logarithmic Error (RMSLE)

D Confusion Matrix

💡 Hint

Consider metrics that evaluate ranked lists and relevance.

Precision at K measures how many of the top K ranked documents are relevant, which fits ranking evaluation.

Practice

1. What does document similarity ranking help us do in natural language processing?

easy

A. Find how related two texts are based on their content

B. Translate documents into different languages

C. Summarize long documents into short ones

D. Detect spelling errors in documents

Solution

1. Step 1: Understand the purpose of document similarity ranking

   Document similarity ranking is used to compare texts and find how closely related they are based on their content.

2. Step 2: Identify the correct description

   Among the options, only finding relatedness of texts matches the purpose of document similarity ranking.

3. Final Answer:

   Find how related two texts are based on their content -> Option A

4. Quick Check:

   Document similarity ranking = Find related texts [OK]

Hint: Think: similarity means how close or related texts are [OK]

Common Mistakes:

• Confusing similarity ranking with translation
• Thinking it summarizes documents
• Mixing it up with spell checking

2. Which of the following is the correct way to compute cosine similarity between two vectors A and B in Python using NumPy?

easy

A. np.dot(A, B) * (np.linalg.norm(A) + np.linalg.norm(B))

B. np.dot(A, B) / (np.linalg.norm(A) * np.linalg.norm(B))

C. np.dot(A, B) - (np.linalg.norm(A) * np.linalg.norm(B))

D. np.dot(A, B) / (np.linalg.norm(A) + np.linalg.norm(B))

Solution

1. Step 1: Recall cosine similarity formula

   Cosine similarity = dot product of vectors divided by product of their magnitudes (norms).

2. Step 2: Match formula to code

   np.dot(A, B) / (np.linalg.norm(A) * np.linalg.norm(B)) correctly implements this formula using np.dot and np.linalg.norm.

3. Final Answer:

   np.dot(A, B) / (np.linalg.norm(A) * np.linalg.norm(B)) -> Option B

4. Quick Check:

   Cosine similarity formula = np.dot(A, B) / (np.linalg.norm(A) * np.linalg.norm(B)) [OK]

Hint: Cosine similarity = dot product ÷ (norm A x norm B) [OK]

Common Mistakes:

• Adding norms instead of multiplying
• Subtracting norms instead of dividing
• Multiplying dot product by sum of norms

3. Given the following Python code using TF-IDF and cosine similarity, what will be the printed similarity score between the two documents?

from sklearn.feature_extraction.text import TfidfVectorizer
from sklearn.metrics.pairwise import cosine_similarity

docs = ['apple orange banana', 'banana fruit apple']
vectorizer = TfidfVectorizer()
X = vectorizer.fit_transform(docs)
sim_score = cosine_similarity(X[0], X[1])[0][0]
print(round(sim_score, 2))

medium

A. 0.50

B. 1.00

C. 0.58

D. 0.00

Solution

1. Step 1: Understand TF-IDF vectorization of similar documents

   Both documents share words 'apple' and 'banana' and have similar content, so their TF-IDF vectors will be close.

2. Step 2: Calculate cosine similarity between vectors

   Cosine similarity between these vectors will be high but less than 1, approximately 0.58 after rounding.

3. Final Answer:

   0.58 -> Option C

4. Quick Check:

   Similarity of similar docs ≈ 0.58 [OK]

Hint: Similar docs have cosine similarity close to 1 but not exactly 1 [OK]

Common Mistakes:

• Assuming similarity is exactly 1 for similar texts
• Confusing cosine similarity with Euclidean distance
• Ignoring TF-IDF weighting effects

4. The following code attempts to compute cosine similarity between two documents but raises an error. What is the main issue?

from sklearn.feature_extraction.text import TfidfVectorizer
from sklearn.metrics.pairwise import cosine_similarity

docs = ['cat dog', 'dog mouse']
vectorizer = TfidfVectorizer()
X = vectorizer.fit_transform(docs).toarray()
sim_score = cosine_similarity(X[0], X[1])
print(sim_score)

medium

A. cosine_similarity expects 2D arrays, but X[0] and X[1] are 1D arrays

B. TfidfVectorizer cannot process documents with different words

C. cosine_similarity requires dense arrays, not sparse matrices

D. The print statement has a typo in variable name

Solution

1. Step 1: Check input types for cosine_similarity

   cosine_similarity expects 2D arrays, but X[0] and X[1] are 1D arrays (shape (n_features,)).

2. Step 2: Understand how to fix the error

   Use X[0:1] and X[1:2] or reshape them properly to avoid the error.

3. Final Answer:

   cosine_similarity expects 2D arrays, but X[0] and X[1] are 1D arrays -> Option A

4. Quick Check:

   cosine_similarity input shape = 2D arrays [OK]

Hint: cosine_similarity needs 2D arrays, not single vectors [OK]

Common Mistakes:

• Thinking TfidfVectorizer fails on different words
• Thinking cosine_similarity accepts 1D arrays
• Overlooking variable name typos

5. You have a collection of 3 documents: ['apple banana', 'banana orange', 'apple orange banana']. You want to rank these documents by similarity to the query 'banana apple'. Which approach correctly ranks them from most to least similar using TF-IDF and cosine similarity?

hard

A. Use raw word counts without TF-IDF, rank by Euclidean distance ascending

B. Count word overlaps between query and documents, rank by overlap count ascending

C. Compute TF-IDF vectors but rank by cosine similarity scores ascending

D. Compute TF-IDF vectors for all documents and query, then rank by cosine similarity scores descending

Solution

1. Step 1: Understand ranking by similarity

   To rank documents by similarity to a query, compute vector representations and measure similarity scores, then sort descending (highest similarity first).

2. Step 2: Identify correct method

   TF-IDF vectors and cosine similarity are standard; ranking by descending cosine similarity scores is correct.

3. Final Answer:

   Compute TF-IDF vectors for all documents and query, then rank by cosine similarity scores descending -> Option D

4. Quick Check:

   Similarity ranking = cosine similarity descending [OK]

Hint: Rank documents by highest cosine similarity to query [OK]

Common Mistakes:

• Ranking by ascending similarity (lowest first)
• Using raw counts without weighting
• Ranking by overlap count ascending