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NextJSframework~10 mins

Catch-all API routes in NextJS - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to define a catch-all API route filename in Next.js.

NextJS
export default function handler(req, res) {
  res.status(200).json({ message: 'Hello from [1] route' });
}

// Filename: pages/api/[1].js
Drag options to blanks, or click blank then click option'
A[slug]
B[...slug]
Cindex
Dapi
Attempts:
3 left
💡 Hint
Common Mistakes
Using single brackets like [slug] only catches one segment.
Using 'index' or 'api' does not create a catch-all route.
2fill in blank
medium

Complete the code to access the catch-all route parameters inside the API handler.

NextJS
export default function handler(req, res) {
  const { [1] } = req.query;
  res.status(200).json({ params: [1] });
}
Drag options to blanks, or click blank then click option'
Apath
Bparams
Cquery
Dslug
Attempts:
3 left
💡 Hint
Common Mistakes
Using req.query.params or req.query.path which do not match the filename.
Trying to access req.query.query which is not correct.
3fill in blank
hard

Fix the error in the catch-all API route handler to correctly handle no parameters.

NextJS
export default function handler(req, res) {
  const { slug = [] } = req.query;
  if ([1]) {
    res.status(200).json({ message: 'No parameters provided' });
  } else {
    res.status(200).json({ params: slug });
  }
}
Drag options to blanks, or click blank then click option'
Aslug === undefined
Bslug === null
Cslug.length === 0
Dslug.length > 0
Attempts:
3 left
💡 Hint
Common Mistakes
Checking if slug is null or undefined, which it never is due to default value.
Checking if slug.length > 0 which is true when parameters exist, not when missing.
4fill in blank
hard

Fill both blanks to create an optional catch-all API route filename and access its parameters.

NextJS
// Filename: pages/api/[1].js

export default function handler(req, res) {
  const { [2] = [] } = req.query;
  res.status(200).json({ params: [2] });
}
Drag options to blanks, or click blank then click option'
A[[...slug]]
B[...slug]
Cslug
Dparams
Attempts:
3 left
💡 Hint
Common Mistakes
Using single brackets for optional catch-all routes.
Using 'params' instead of the parameter name from the filename.
5fill in blank
hard

Fill all three blanks to return a JSON response with the first parameter, all parameters, and a message.

NextJS
export default function handler(req, res) {
  const { [1] = [] } = req.query;
  const firstParam = [2][0] || null;
  res.status(200).json({
    first: firstParam,
    all: [3],
    message: firstParam ? `First param is ${firstParam}` : 'No params'
  });
}
Drag options to blanks, or click blank then click option'
Aslug
Bparams
Dquery
Attempts:
3 left
💡 Hint
Common Mistakes
Using different names for the parameter causing undefined errors.
Not handling the case when no parameters are passed.

Practice

(1/5)
1. What does a catch-all API route file named [...slug].js in Next.js do?
easy
A. It catches all URL paths that match and provides the parts as an array in req.query.slug.
B. It only catches the root API path and ignores nested paths.
C. It catches only one specific URL path exactly matching slug.
D. It disables all API routes in the folder.

Solution

  1. Step 1: Understand catch-all route naming

    In Next.js, files named with [...name].js catch all nested paths under that route.
  2. Step 2: Check how parameters are passed

    The parts of the URL matched are passed as an array in req.query.name, here slug.
  3. Final Answer:

    It catches all URL paths that match and provides the parts as an array in req.query.slug. -> Option A
  4. Quick Check:

    Catch-all route = array in req.query [OK]
Hint: Catch-all uses [...name].js and returns array in req.query[name] [OK]
Common Mistakes:
  • Thinking it catches only one path instead of many
  • Expecting a string instead of an array in req.query
  • Confusing catch-all with optional catch-all routes
2. Which of the following is the correct filename for a catch-all API route in Next.js?
easy
A. [slug].js
B. [...slug].js
C. slug.js
D. [slug...].js

Solution

  1. Step 1: Recall catch-all route syntax

    Catch-all routes use three dots inside square brackets before the name, like [...slug].js.
  2. Step 2: Compare options

    Only [...slug].js matches the correct syntax for catch-all routes.
  3. Final Answer:

    [...slug].js -> Option B
  4. Quick Check:

    Catch-all filename = [...name].js [OK]
Hint: Catch-all filenames always have three dots inside brackets [OK]
Common Mistakes:
  • Using single brackets without dots for catch-all
  • Placing dots outside brackets
  • Missing brackets entirely
3. Given a catch-all API route file pages/api/[...params].js with this handler:
export default function handler(req, res) {
  res.json(req.query.params);
}

What will be the JSON response for a request to /api/a/b/c?
medium
A. "a/b/c"
B. {"params": "a/b/c"}
C. ["a", "b", "c"]
D. null

Solution

  1. Step 1: Understand catch-all parameter passing

    The catch-all [...params] captures all path parts as an array in req.query.params.
  2. Step 2: Check the handler response

    The handler returns req.query.params as JSON, so the response is the array of parts.
  3. Final Answer:

    ["a", "b", "c"] -> Option C
  4. Quick Check:

    Catch-all returns array of path parts [OK]
Hint: Catch-all returns array of URL parts in req.query [OK]
Common Mistakes:
  • Expecting a string instead of an array
  • Confusing JSON structure returned
  • Not recognizing catch-all returns array
4. You wrote a catch-all API route pages/api/[...slug].js but when you request /api (no extra path), you get an error. What is the likely cause?
medium
A. You forgot to export the handler function.
B. The file name is incorrect; it should be [slug].js.
C. API routes cannot have dynamic segments.
D. Catch-all routes require at least one path segment; use optional catch-all [[...slug]].js instead.

Solution

  1. Step 1: Understand catch-all vs optional catch-all

    Catch-all [...slug].js requires at least one path part; it does not match the base path alone.
  2. Step 2: Identify fix for base path requests

    To handle base path /api with no extra parts, use optional catch-all [[...slug]].js.
  3. Final Answer:

    Catch-all routes require at least one path segment; use optional catch-all [[...slug]].js instead. -> Option D
  4. Quick Check:

    Catch-all needs path parts; optional catch-all handles empty [OK]
Hint: Use [[...name]].js for optional catch-all including empty path [OK]
Common Mistakes:
  • Expecting catch-all to match empty path
  • Misnaming the file without brackets
  • Ignoring export of handler function
5. You want to create a catch-all API route that returns a JSON object with keys for each path part and their index, for example, for /api/a/b/c it returns {"0": "a", "1": "b", "2": "c"}. Which handler code inside pages/api/[...parts].js achieves this?
hard
A. export default function handler(req, res) { const obj = {}; req.query.parts.forEach((p, i) => { obj[i] = p; }); res.json(obj); }
B. export default function handler(req, res) { res.json(req.query.parts.join(',')); }
C. export default function handler(req, res) { res.json({ parts: req.query.parts }); }
D. export default function handler(req, res) { res.json(req.query.parts.length); }

Solution

  1. Step 1: Understand the input and desired output

    The catch-all parameter parts is an array of path parts. We want to create an object with keys as indices and values as parts.
  2. Step 2: Check which code builds the object correctly

    export default function handler(req, res) { const obj = {}; req.query.parts.forEach((p, i) => { obj[i] = p; }); res.json(obj); } loops over req.query.parts and assigns each part to the object with its index as key, then returns it as JSON.
  3. Final Answer:

    export default function handler(req, res) { const obj = {}; req.query.parts.forEach((p, i) => { obj[i] = p; }); res.json(obj); } -> Option A
  4. Quick Check:

    Loop parts to object with index keys = export default function handler(req, res) { const obj = {}; req.query.parts.forEach((p, i) => { obj[i] = p; }); res.json(obj); } [OK]
Hint: Use forEach to map array parts to object keys [OK]
Common Mistakes:
  • Returning array or string instead of object
  • Not looping to create object keys
  • Returning length instead of parts
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