Bird
Raised Fist0
MySQLquery~20 mins

Password policies in MySQL - Practice Problems & Coding Challenges

Choose your learning style10 modes available
Challenge - 5 Problems
🎖️
Password Policy Master
Get all challenges correct to earn this badge!
Test your skills under time pressure!
❓ query_result
intermediate
2:00remaining
Check password expiration setting
What is the output of the following query that checks the global password expiration policy in MySQL?
MySQL
SHOW VARIABLES LIKE 'default_password_lifetime';
A[{"Variable_name": "default_password_lifetime", "Value": "90"}]
B[{"Variable_name": "default_password_lifetime", "Value": "0"}]
C[{"Variable_name": "default_password_lifetime", "Value": "180"}]
D[{"Variable_name": "default_password_lifetime", "Value": "30"}]
Attempts:
2 left
💡 Hint
The default value 0 means passwords never expire unless changed.
📝 Syntax
intermediate
2:00remaining
Identify the correct syntax to enforce password expiration
Which option correctly sets the password expiration policy to 60 days for all users in MySQL?
AALTER USER ALL PASSWORD EXPIRE INTERVAL 60 DAY;
BSET PASSWORD EXPIRE INTERVAL 60 DAY FOR ALL;
CSET GLOBAL default_password_lifetime = 60;
DALTER GLOBAL PASSWORD LIFETIME 60 DAYS;
Attempts:
2 left
💡 Hint
The setting is a global variable, not a user-level command.
🧠 Conceptual
advanced
2:00remaining
Understanding password validation plugin
Which statement best describes the role of the MySQL validate_password plugin?
AIt manages user account lockout after failed login attempts.
BIt automatically expires passwords after a set number of days.
CIt encrypts passwords stored in the database.
DIt enforces password strength rules like length and character types during password changes.
Attempts:
2 left
💡 Hint
Think about what controls password complexity requirements.
🔧 Debug
advanced
2:00remaining
Why does this password expiration command fail?
A DBA runs this command to expire a user's password immediately but gets an error:

ALTER USER 'alice'@'localhost' PASSWORD EXPIRE INTERVAL 0 DAY;

What is the reason for the failure?
AThe INTERVAL value cannot be zero; use PASSWORD EXPIRE without INTERVAL to expire immediately.
BThe user 'alice' does not exist in the database.
CThe syntax requires the keyword 'SET' before PASSWORD EXPIRE.
DPassword expiration cannot be set per user in MySQL.
Attempts:
2 left
💡 Hint
Check the correct syntax for immediate password expiration.
❓ optimization
expert
3:00remaining
Optimize password policy enforcement for many users
You want to enforce a strong password policy and expiration for thousands of users efficiently. Which approach is best?
ASet global variables <code>default_password_lifetime</code> and enable <code>validate_password</code> plugin once, so all users inherit policies automatically.
BManually run <code>ALTER USER ... PASSWORD EXPIRE</code> and password validation for each user individually.
CCreate a trigger on the user table to check password strength and expiration on every login.
DDisable password expiration and rely on users to change passwords voluntarily.
Attempts:
2 left
💡 Hint
Think about scalability and central management.

Practice

(1/5)
1. What is the purpose of MySQL's validate_password_policy variable?
easy
A. To set rules for creating strong passwords
B. To control user access privileges
C. To define database storage engines
D. To manage query cache size

Solution

  1. Step 1: Understand the variable name

    The variable validate_password_policy relates to password validation rules.
  2. Step 2: Identify its function

    It sets rules to ensure passwords are strong and secure.
  3. Final Answer:

    To set rules for creating strong passwords -> Option A
  4. Quick Check:

    Password policy = Set rules for strong passwords [OK]
Hint: Policy variables control password strength rules [OK]
Common Mistakes:
  • Confusing password policy with user privileges
  • Thinking it manages database storage
  • Assuming it controls query cache
2. Which of the following is the correct syntax to check the current password policy level in MySQL?
easy
A. SHOW PASSWORD POLICY;
B. SELECT * FROM validate_password_policy;
C. SHOW VARIABLES LIKE 'validate_password_policy';
D. GET VARIABLES 'validate_password_policy';

Solution

  1. Step 1: Recall how to view system variables

    MySQL uses SHOW VARIABLES LIKE 'variable_name'; to display variable values.
  2. Step 2: Match the variable name

    The variable for password policy is validate_password_policy, so the correct syntax is SHOW VARIABLES LIKE 'validate_password_policy';
  3. Final Answer:

    SHOW VARIABLES LIKE 'validate_password_policy'; -> Option C
  4. Quick Check:

    SHOW VARIABLES LIKE 'validate_password_policy' [OK]
Hint: Use SHOW VARIABLES LIKE for system settings [OK]
Common Mistakes:
  • Using SELECT on a variable name
  • Trying non-existent commands like SHOW PASSWORD POLICY
  • Using GET VARIABLES which is invalid syntax
3. Given the following commands executed in MySQL:
SET GLOBAL validate_password_length = 10;
SHOW VARIABLES LIKE 'validate_password_length';

What will be the output of the SHOW VARIABLES command?
medium
A. Variable_name: validate_password_length, Value: 10
B. Variable_name: validate_password_length, Value: 8
C. Syntax error
D. Variable_name: validate_password_policy, Value: 10

Solution

  1. Step 1: Understand the SET GLOBAL command

    The command sets the global password length requirement to 10 characters.
  2. Step 2: SHOW VARIABLES output

    The SHOW VARIABLES LIKE 'validate_password_length'; will display the current value, which is now 10.
  3. Final Answer:

    Variable_name: validate_password_length, Value: 10 -> Option A
  4. Quick Check:

    SET GLOBAL changes variable, SHOW displays updated value [OK]
Hint: SET GLOBAL changes variable, SHOW displays current value [OK]
Common Mistakes:
  • Expecting default value instead of updated
  • Confusing variable names
  • Assuming syntax error from SET GLOBAL
4. You tried to set the password policy level with this command:
SET GLOBAL validate_password_policy = 'STRONG';

But MySQL returned an error. What is the likely cause?
medium
A. The command requires quotes around the variable name
B. The variable name is incorrect
C. You must use SET SESSION instead of SET GLOBAL
D. The value should be an integer, not a string

Solution

  1. Step 1: Check variable type for validate_password_policy

    This variable expects an integer value (0,1,2) representing policy levels, not strings.
  2. Step 2: Understand error cause

    Using a string like 'STRONG' causes a type mismatch error.
  3. Final Answer:

    The value should be an integer, not a string -> Option D
  4. Quick Check:

    Policy level = integer, not string [OK]
Hint: Policy levels use numbers, not words [OK]
Common Mistakes:
  • Using string values instead of integers
  • Mistyping variable name
  • Confusing SET GLOBAL with SET SESSION
5. You want to enforce a password policy that requires passwords to be at least 12 characters long, include mixed case letters, numbers, and special characters. Which combination of MySQL variables should you set to achieve this?
hard
A. SET GLOBAL validate_password_length = 10; SET GLOBAL validate_password_policy = 0;
B. SET GLOBAL validate_password_length = 12; SET GLOBAL validate_password_policy = 2;
C. SET GLOBAL validate_password_length = 12; SET GLOBAL validate_password_policy = 1;
D. SET GLOBAL validate_password_length = 8; SET GLOBAL validate_password_policy = 0;

Solution

  1. Step 1: Understand password length requirement

    You want at least 12 characters, so validate_password_length must be set to 12.
  2. Step 2: Understand policy levels

    Policy level 2 (STRONG) requires mixed case, numbers, and special characters.
  3. Step 3: Match variables to requirements

    Setting validate_password_policy = 2 and length to 12 enforces all requirements.
  4. Final Answer:

    SET GLOBAL validate_password_length = 12; SET GLOBAL validate_password_policy = 2; -> Option B
  5. Quick Check:

    Length 12 + policy 2 = strong password rules [OK]
Hint: Policy 2 = strong; length sets minimum characters [OK]
Common Mistakes:
  • Using policy 0 or 1 which are weaker
  • Setting length less than required
  • Confusing policy levels with string values
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard