$slice modifier with $push in MongoDB - Time & Space Complexity

Time Complexity: $slice modifier with $push

O(n)

Understanding Time Complexity

When using the $slice modifier with $push in MongoDB, it's important to understand how the operation's time grows as the array size changes.

We want to know how the cost of adding and trimming elements scales with the array length.

Scenario Under Consideration

Analyze the time complexity of the following MongoDB update operation.

db.collection.updateOne(
  { _id: 1 },
  { $push: { scores: { $each: [90], $slice: -5 } } }
)
    

This code adds a new score to the scores array and keeps only the last 5 elements.

Identify Repeating Operations

Look for repeated work inside the update.

• Primary operation: Trimming the array to keep only the last 5 elements after pushing.
• How many times: The trimming checks elements up to the array length, which can vary.

How Execution Grows With Input

As the array grows larger, trimming to keep only 5 elements means scanning more elements before cutting.

Input Size (n)	Approx. Operations
10	About 10 checks to trim
100	About 100 checks to trim
1000	About 1000 checks to trim

Pattern observation: The trimming work grows roughly in direct proportion to the array size.

Final Time Complexity

Time Complexity: O(n)

This means the time to push and slice grows linearly with the size of the array.

Common Mistake

[X] Wrong: "Using $slice with $push always runs in constant time because it only keeps a fixed number of elements."

[OK] Correct: Even though the final array size is fixed, MongoDB must scan the whole array to trim it, so the time depends on the current array length.

Interview Connect

Understanding how array updates scale helps you explain performance trade-offs clearly and shows you know how database operations behave with growing data.

Self-Check

What if we replaced $slice with a fixed array size limit in the schema? How would that affect the time complexity?

Practice

1. What does the $slice modifier do when used with $push in MongoDB?

easy

A. Duplicates the array elements before pushing new ones

B. Removes all elements from the array before adding new ones

C. Limits the size of the array after adding new elements

D. Sorts the array elements in ascending order

Solution

1. Step 1: Understand $push behavior

   $push adds new elements to an array field in a document.

2. Step 2: Role of $slice modifier

   $slice limits the array size after pushing, keeping only a specified number of elements.

3. Final Answer:

   Limits the size of the array after adding new elements -> Option C

4. Quick Check:

   $slice limits array size [OK]

Hint: Remember: $slice trims array size after $push [OK]

Common Mistakes:

• Thinking $slice removes elements before pushing
• Confusing $slice with sorting or duplicating
• Assuming $slice adds elements instead of limiting

2. Which of the following is the correct syntax to push multiple items and limit the array size to 3 using $slice in MongoDB?

easy

A. { $push: { scores: { $each: [90, 85], $slice: 3 } } }

B. { $push: { scores: { $slice: [3], $each: [90, 85] } } }

C. { $push: { scores: { $each: 3, $slice: [90, 85] } } }

D. { $push: { scores: { $slice: [90, 85], $each: 3 } } }

Solution

1. Step 1: Identify correct order of modifiers

   The $each modifier must come before $slice inside $push.

2. Step 2: Validate syntax correctness

   { $push: { scores: { $each: [90, 85], $slice: 3 } } } correctly uses $each: [90, 85] followed by $slice: 3 to limit array size.

3. Final Answer:

   { $push: { scores: { $each: [90, 85], $slice: 3 } } } -> Option A

4. Quick Check:

   $each before $slice [OK]

Hint: Put $each before $slice inside $push [OK]

Common Mistakes:

• Swapping order of $each and $slice
• Using arrays instead of numbers for $slice
• Placing $slice outside $push

3. Given the document { _id: 1, items: [1, 2, 3, 4] }, what will be the items array after running this update?
db.collection.updateOne({ _id: 1 }, { $push: { items: { $each: [5, 6], $slice: -4 } } })

medium

A. [3, 4, 5, 6]

B. [1, 2, 3, 4, 5, 6]

C. [2, 3, 4, 5]

D. [5, 6]

Solution

1. Step 1: Understand $each and $slice with negative value

   $each adds [5, 6] to the array. $slice: -4 keeps the last 4 elements of the array.

2. Step 2: Calculate new array content

   Original array: [1, 2, 3, 4]
   After push: [1, 2, 3, 4, 5, 6]
   Apply $slice: -4: keep last 4 elements -> [3, 4, 5, 6]

3. Final Answer:

   [3, 4, 5, 6] -> Option A

4. Quick Check:

   Negative $slice keeps last elements [OK]

Hint: Negative $slice keeps last N elements [OK]

Common Mistakes:

• Ignoring $slice and keeping all elements
• Using positive $slice logic incorrectly
• Removing new elements instead of old

4. You run this update:
db.collection.updateOne({ _id: 2 }, { $push: { logs: { $each: ["a", "b"], $slice: 1 } } })
But the array logs ends up with 1 element that is an old one instead of a newly pushed one. What is the likely mistake?

medium

A. Not specifying $position causes elements to append incorrectly

B. Missing $each causes syntax error

C. Using $slice with a negative number causes array to clear

D. Using positive $slice keeps first elements instead of newest ones

Solution

1. Step 1: Understand positive $slice behavior

   Positive $slice: 1 keeps only the first element of the array after push.

2. Step 2: Why old elements remain

   Positive $slice: 1 keeps the first (oldest) element of the resulting array since new elements are appended to the end.

3. Step 3: Common confusion

   Positive $slice keeps elements from the start, so if you want to keep the latest elements, use negative $slice.

4. Final Answer:

   Using positive $slice keeps first elements instead of newest ones -> Option D

5. Quick Check:

   Positive $slice keeps start elements [OK]

Hint: Use negative $slice to keep newest elements [OK]

Common Mistakes:

• Confusing positive and negative $slice behavior
• Omitting $each inside $push
• Expecting $slice to remove elements before push

5. You want to keep only the 5 most recent messages in a chat array after adding new messages ["msg4", "msg5"]. The current array is ["msg1", "msg2", "msg3", "msg4"]. Which update query correctly achieves this?

hard

A. db.collection.updateOne({ _id: 1 }, { $push: { chat: { $each: ["msg4", "msg5"], $slice: 5 } } })

B. db.collection.updateOne({ _id: 1 }, { $push: { chat: { $each: ["msg4", "msg5"], $slice: -5 } } })

C. db.collection.updateOne({ _id: 1 }, { $push: { chat: { $each: ["msg4", "msg5"], $slice: 2 } } })

D. db.collection.updateOne({ _id: 1 }, { $push: { chat: { $each: ["msg4", "msg5"], $slice: -2 } } })

Solution

1. Step 1: Understand the goal

   We want to add two new messages and keep only the 5 most recent messages in the array.

2. Step 2: Use $each and negative $slice

   $each adds multiple items. Negative $slice: -5 keeps the last 5 elements, which are the most recent.

3. Step 3: Check options

   db.collection.updateOne({ _id: 1 }, { $push: { chat: { $each: ["msg4", "msg5"], $slice: -5 } } }) uses $slice: -5 correctly. db.collection.updateOne({ _id: 1 }, { $push: { chat: { $each: ["msg4", "msg5"], $slice: 5 } } }) keeps first 5 elements (oldest), C keeps only 2 elements, D keeps last 2 elements, which is too few.

4. Final Answer:

   db.collection.updateOne({ _id: 1 }, { $push: { chat: { $each: ["msg4", "msg5"], $slice: -5 } } }) -> Option B

5. Quick Check:

   Negative $slice keeps newest 5 elements [OK]

Hint: Use negative $slice with $each to keep recent items [OK]

Common Mistakes:

• Using positive $slice which keeps oldest items
• Setting $slice too small and losing messages
• Forgetting $each when adding multiple items