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One-to-one embedding pattern in MongoDB - Practice Problems & Coding Challenges

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Challenge - 5 Problems
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One-to-One Embedding Master
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❓ query_result
intermediate
2:00remaining
Find the embedded document in a one-to-one pattern

Given a collection users where each user document embeds a single profile document, what will be the output of the following query?

{ _id: 1, name: "Alice", profile: { age: 30, city: "NY" } }

Query:

db.users.findOne({ _id: 1 }, { "profile.city": 1, _id: 0 })
MongoDB
db.users.findOne({ _id: 1 }, { "profile.city": 1, _id: 0 })
A{"profile.city": "NY"}
B{"profile": {"city": "NY"}}
C{"city": "NY"}
D{"profile": {"age": 30, "city": "NY"}}
Attempts:
2 left
💡 Hint

Projection returns the embedded document fields as nested objects.

📝 Syntax
intermediate
2:00remaining
Identify the correct syntax for embedding one-to-one documents

Which of the following MongoDB insert statements correctly embeds a one-to-one address document inside a customer document?

Adb.customers.insertOne({ _id: 101, name: "Bob" }, { address: { street: "Main St", number: 123 } })
Bdb.customers.insertOne({ _id: 101, name: "Bob" }, { $set: { address: { street: "Main St", number: 123 } } })
Cdb.customers.insertOne({ _id: 101, name: "Bob", address: [ { street: "Main St", number: 123 } ] })
Ddb.customers.insertOne({ _id: 101, name: "Bob", address: { street: "Main St", number: 123 } })
Attempts:
2 left
💡 Hint

Embedding means nesting the document inside the main document in one insert.

❓ optimization
advanced
2:00remaining
Optimize query performance for one-to-one embedded documents

You have a products collection where each product embeds a specs document. You want to frequently query products by a field inside specs, for example specs.weight. What is the best way to optimize these queries?

ACreate an index on <code>specs.weight</code> field
BCreate a text index on the entire <code>specs</code> document
CSplit <code>specs</code> into a separate collection and use references
DUse aggregation pipeline to filter <code>specs.weight</code> after fetching all products
Attempts:
2 left
💡 Hint

Indexes speed up queries on specific fields.

🔧 Debug
advanced
2:00remaining
Debug why embedded document is missing in query result

You have documents with embedded profile in users. You run this query:

db.users.find({}, { name: 1 })

But the profile field is missing in the results. Why?

MongoDB
db.users.find({}, { name: 1 })
ABecause projection only includes <code>name</code> and excludes all other fields including <code>profile</code>
BBecause the query syntax is invalid and returns no fields
CBecause <code>profile</code> field is empty in all documents
DBecause <code>profile</code> is not embedded but referenced
Attempts:
2 left
💡 Hint

Projection controls which fields appear in results.

🧠 Conceptual
expert
3:00remaining
Why choose one-to-one embedding over referencing?

In MongoDB, when designing a schema for a one-to-one relationship, why might embedding the related document be better than using references?

AEmbedding enforces stronger data consistency by using foreign key constraints
BEmbedding allows unlimited growth of the embedded document without size limits
CEmbedding reduces the need for joins and improves read performance by storing related data together
DEmbedding automatically creates indexes on all embedded fields
Attempts:
2 left
💡 Hint

Think about how data is stored and accessed in MongoDB.

Practice

(1/5)
1. What is the main advantage of using the one-to-one embedding pattern in MongoDB?
easy
A. It requires complex joins to retrieve related data.
B. It splits data into multiple collections to reduce document size.
C. It stores related data inside a single document for faster reads.
D. It duplicates data across collections for backup.

Solution

  1. Step 1: Understand one-to-one embedding

    One-to-one embedding stores related data inside the same document instead of separate collections.
  2. Step 2: Identify the advantage

    This approach simplifies queries and improves read speed by avoiding joins.
  3. Final Answer:

    It stores related data inside a single document for faster reads. -> Option C
  4. Quick Check:

    Embedding = faster reads [OK]
Hint: Embedding keeps related data together for quick access [OK]
Common Mistakes:
  • Thinking embedding splits data into multiple collections
  • Assuming embedding requires joins
  • Confusing embedding with data duplication
2. Which of the following is the correct way to embed a profile document inside a user document in MongoDB?
easy
A. { _id: 1, name: 'Alice' }, profile: { age: 30, city: 'NY' }
B. { _id: 1, name: 'Alice', profile: { age: 30, city: 'NY' } }
C. { _id: 1, name: 'Alice', profile: [ { age: 30, city: 'NY' } ] }
D. { _id: 1, name: 'Alice', profile: 'age:30, city:NY' }

Solution

  1. Step 1: Check embedding syntax

    Embedding means nesting a document inside another document as a field with an object value.
  2. Step 2: Identify correct JSON structure

    { _id: 1, name: 'Alice', profile: { age: 30, city: 'NY' } } correctly nests the profile as an object inside user. { _id: 1, name: 'Alice' }, profile: { age: 30, city: 'NY' } separates profile outside user. { _id: 1, name: 'Alice', profile: [ { age: 30, city: 'NY' } ] } uses an array unnecessarily. { _id: 1, name: 'Alice', profile: 'age:30, city:NY' } stores profile as a string, not an object.
  3. Final Answer:

    { _id: 1, name: 'Alice', profile: { age: 30, city: 'NY' } } -> Option B
  4. Quick Check:

    Embedded document = nested object [OK]
Hint: Embed as nested object, not separate or string [OK]
Common Mistakes:
  • Placing embedded document outside main document
  • Using array instead of object for one-to-one
  • Storing embedded data as string
3. Given the document { _id: 1, name: 'Bob', address: { street: 'Main St', city: 'LA' } }, what will be the result of the query db.users.findOne({ _id: 1 })?
medium
A. { _id: 1, name: 'Bob' }
B. null
C. { address: { street: 'Main St', city: 'LA' } }
D. { _id: 1, name: 'Bob', address: { street: 'Main St', city: 'LA' } }

Solution

  1. Step 1: Understand findOne query

    The query searches for a document with _id equal to 1 and returns the whole document.
  2. Step 2: Check document structure

    The document includes embedded address inside user, so the full document is returned.
  3. Final Answer:

    { _id: 1, name: 'Bob', address: { street: 'Main St', city: 'LA' } } -> Option D
  4. Quick Check:

    findOne returns full document [OK]
Hint: findOne returns entire matching document including embedded [OK]
Common Mistakes:
  • Expecting only top-level fields returned
  • Thinking embedded fields are separate documents
  • Assuming query returns null if embedded exists
4. You have this document: { _id: 2, name: 'Carol', profile: { age: 25, city: 'Chicago' } }. Which update command correctly changes the city to 'Boston' using one-to-one embedding?
medium
A. db.users.updateOne({ _id: 2 }, { $set: { 'profile.city': 'Boston' } })
B. db.users.updateOne({ _id: 2 }, { $set: { profile: 'Boston' } })
C. db.users.updateOne({ _id: 2 }, { $set: { city: 'Boston' } })
D. db.users.updateOne({ _id: 2 }, { $set: { 'profile[city]': 'Boston' } })

Solution

  1. Step 1: Identify correct update syntax for embedded field

    To update a nested field, use dot notation like 'profile.city'.
  2. Step 2: Check each option

    db.users.updateOne({ _id: 2 }, { $set: { 'profile.city': 'Boston' } }) uses correct dot notation. db.users.updateOne({ _id: 2 }, { $set: { profile: 'Boston' } }) replaces entire profile with string. db.users.updateOne({ _id: 2 }, { $set: { city: 'Boston' } }) tries to set city at top level, which doesn't exist. db.users.updateOne({ _id: 2 }, { $set: { 'profile[city]': 'Boston' } }) uses invalid bracket notation.
  3. Final Answer:

    db.users.updateOne({ _id: 2 }, { $set: { 'profile.city': 'Boston' } }) -> Option A
  4. Quick Check:

    Use dot notation to update embedded fields [OK]
Hint: Use dot notation to update embedded fields [OK]
Common Mistakes:
  • Replacing whole embedded document instead of one field
  • Using incorrect field path without dot notation
  • Using invalid bracket notation in update
5. You want to design a MongoDB schema for users and their passports using one-to-one embedding. Which design is best and why?
hard
A. Embed passport details inside user document because passports are small and tightly linked.
B. Store passports in a separate collection and reference user IDs to avoid large documents.
C. Duplicate passport data in both user and passport collections for faster writes.
D. Store passport as a string field inside user document to simplify queries.

Solution

  1. Step 1: Analyze data relationship and size

    Passports are small and tightly connected to users, perfect for embedding.
  2. Step 2: Choose embedding benefits

    Embedding keeps related data together, simplifies queries, and improves read speed.
  3. Step 3: Evaluate other options

    Store passports in a separate collection and reference user IDs to avoid large documents adds complexity with references. Duplicate passport data in both user and passport collections for faster writes duplicates data causing inconsistency. Store passport as a string field inside user document to simplify queries stores data as string losing structure.
  4. Final Answer:

    Embed passport details inside user document because passports are small and tightly linked. -> Option A
  5. Quick Check:

    Small, tightly linked data = embed [OK]
Hint: Embed small, tightly linked data for simplicity and speed [OK]
Common Mistakes:
  • Choosing references for small one-to-one data
  • Duplicating data causing inconsistency
  • Storing structured data as plain string
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