$first and $last accumulators in MongoDB - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does the $first accumulator do in MongoDB aggregation?

The $first accumulator returns the first value from the documents in each group, based on the order they are processed.

beginner

What is the purpose of the $last accumulator in MongoDB aggregation?

The $last accumulator returns the last value from the documents in each group, based on the order they are processed.

intermediate

How does the order of documents affect the results of $first and $last?

The order of documents determines which values $first and $last pick. If documents are not sorted, the results may be unpredictable.

intermediate

Can $first and $last be used without sorting documents first?

Yes, but the values returned depend on the natural order of documents, which may not be consistent. Sorting first ensures predictable results.

beginner

Give a simple example of using $first and $last in a MongoDB aggregation pipeline.

Example: Group sales by product and get the first and last sale dates:

{ $group: { _id: "$product", firstSale: { $first: "$date" }, lastSale: { $last: "$date" } } }

What does the $first accumulator return in a MongoDB aggregation?

A The total count of documents in the group

B The last value in the group based on document order

C The first value in the group based on document order

D The average of all values in the group

$first returns the first value in the group according to the order documents are processed.

Which accumulator returns the last value in each group in MongoDB aggregation?

A $last

B $first

C $max

D $min

$last returns the last value in the group based on document order.

Why is sorting documents important before using $first or $last?

A To reduce memory usage

B To make the results predictable

C To speed up the query

D Sorting is not important

Sorting ensures $first and $last pick values from a known order, making results predictable.

If documents are not sorted, what can happen when using $first and $last?

A They return values based on natural document order, which may be unpredictable

B They return random values

C They always return null

D They cause an error

Without sorting, $first and $last use the natural order, which can vary and be unpredictable.

Which MongoDB stage is typically used before $group to ensure correct $first and $last results?

A $match

B $limit

C $project

D $sort

$sort orders documents so $first and $last return expected values.

Explain how $first and $last accumulators work in MongoDB aggregation and why document order matters.

Think about how MongoDB processes documents in a group.

Describe a scenario where using $first and $last would be useful in a real-world application.

Consider tracking changes over time or events.

Practice

1. What does the $first accumulator do in a MongoDB aggregation pipeline?

easy

A. It returns the last value of a specified field in each group.

B. It counts the number of documents in each group.

C. It sorts the documents in ascending order.

D. It returns the first value of a specified field in each group.

Solution

1. Step 1: Understand the role of $first

   The $first accumulator returns the first value of a specified field from documents in a group.

2. Step 2: Differentiate from other accumulators

   Unlike $last, which returns the last value, $first picks the earliest value based on the document order.

3. Final Answer:

   It returns the first value of a specified field in each group. -> Option D

4. Quick Check:

   $first = first value [OK]

Hint: Remember: $first picks earliest value in group [OK]

Common Mistakes:

• Confusing $first with $last accumulator
• Thinking $first sorts documents automatically
• Assuming $first counts documents

2. Which of the following is the correct syntax to use $last in a MongoDB aggregation $group stage?

easy

A. { $group: { _id: "$category", lastItem: { last: "$item" } } }

B. { $group: { _id: "$category", lastItem: { $first: "$item" } } }

C. { $group: { _id: "$category", lastItem: { $last: "$item" } } }

D. { $group: { _id: "$category", lastItem: { $last: item } } }

Solution

1. Step 1: Identify correct accumulator usage

   The $last accumulator must be used with a field path as a string, like "$item".

2. Step 2: Check syntax correctness

   { $group: { _id: "$category", lastItem: { $last: "$item" } } } correctly uses $last: "$item" inside $group. Options A and C have syntax errors, and B uses $first instead of $last.

3. Final Answer:

   { $group: { _id: "$category", lastItem: { $last: "$item" } } } -> Option C

4. Quick Check:

   Correct $last syntax = { $group: { _id: "$category", lastItem: { $last: "$item" } } } [OK]

Hint: Use $last with field path as string "$field" [OK]

Common Mistakes:

• Omitting quotes around field name
• Using $first instead of $last by mistake
• Writing accumulator name incorrectly

3. Given the collection sales with documents:

{ "_id": 1, "product": "A", "date": "2023-01-01" },
{ "_id": 2, "product": "A", "date": "2023-01-05" },
{ "_id": 3, "product": "B", "date": "2023-01-02" }

What will be the output of this aggregation?

[
  { $sort: { date: 1 } },
  { $group: { _id: "$product", firstSale: { $first: "$date" }, lastSale: { $last: "$date" } } }
]

medium

A. [{ "_id": "A", "firstSale": "2023-01-05", "lastSale": "2023-01-01" }, { "_id": "B", "firstSale": "2023-01-02", "lastSale": "2023-01-02" }]

B. [{ "_id": "A", "firstSale": "2023-01-01", "lastSale": "2023-01-05" }, { "_id": "B", "firstSale": "2023-01-02", "lastSale": "2023-01-02" }]

C. [{ "_id": "A", "firstSale": "2023-01-01", "lastSale": "2023-01-01" }, { "_id": "B", "firstSale": "2023-01-02", "lastSale": "2023-01-02" }]

D. [{ "_id": "A", "firstSale": null, "lastSale": null }, { "_id": "B", "firstSale": null, "lastSale": null }]

Solution

1. Step 1: Sort documents by date ascending

   The $sort stage orders documents by date: A on 2023-01-01, B on 2023-01-02, A on 2023-01-05.

2. Step 2: Group by product and apply $first and $last

   For product A, firstSale is earliest date "2023-01-01", lastSale is latest date "2023-01-05". For B, both firstSale and lastSale are "2023-01-02".

3. Final Answer:

   [{ "_id": "A", "firstSale": "2023-01-01", "lastSale": "2023-01-05" }, { "_id": "B", "firstSale": "2023-01-02", "lastSale": "2023-01-02" }] -> Option B

4. Quick Check:

   Sorted + grouped $first/$last = [{ "_id": "A", "firstSale": "2023-01-01", "lastSale": "2023-01-05" }, { "_id": "B", "firstSale": "2023-01-02", "lastSale": "2023-01-02" }] [OK]

Hint: Sort first, then $first/$last pick earliest/latest values [OK]

Common Mistakes:

• Ignoring $sort stage before $group
• Mixing up $first and $last values
• Assuming $first/$last pick random values

4. You wrote this aggregation but it returns incorrect $last values:

db.orders.aggregate([
  { $group: { _id: "$customer", lastOrder: { $last: "$orderDate" } } }
])

What is the most likely reason?

medium

A. You forgot to sort documents by orderDate before grouping.

B. You used $last instead of $first.

C. The orderDate field is missing in documents.

D. You need to use $max instead of $last.

Solution

1. Step 1: Understand $last depends on document order

   The $last accumulator returns the last value in the current document order within each group.

2. Step 2: Identify missing $sort stage

   Without sorting by orderDate, documents are in arbitrary order, so $last may not return the latest date.

3. Final Answer:

   You forgot to sort documents by orderDate before grouping. -> Option A

4. Quick Check:

   Missing $sort before $group causes wrong $last [OK]

Hint: Always $sort by date before using $last [OK]

Common Mistakes:

• Assuming $last finds max value automatically
• Using $last without sorting documents
• Confusing $last with $max accumulator

5. You have a collection events with documents:

{ "user": "Alice", "timestamp": 100 },
{ "user": "Alice", "timestamp": 200 },
{ "user": "Bob", "timestamp": 150 },
{ "user": "Bob", "timestamp": 50 }

You want to find each user's first and last event timestamps using the $first and $last accumulators. Which aggregation pipeline correctly achieves this?

hard

A. [ { $sort: { timestamp: 1 } }, { $group: { _id: "$user", firstEvent: { $first: "$timestamp" }, lastEvent: { $last: "$timestamp" } } } ]

B. [ { $group: { _id: "$user", firstEvent: { $first: "$timestamp" }, lastEvent: { $last: "$timestamp" } } } ]

C. [ { $sort: { timestamp: -1 } }, { $group: { _id: "$user", firstEvent: { $first: "$timestamp" }, lastEvent: { $last: "$timestamp" } } } ]

D. [ { $group: { _id: "$user", firstEvent: { $min: "$timestamp" }, lastEvent: { $max: "$timestamp" } } } ]

Solution

1. Step 1: Sort events by timestamp ascending

   Sorting by timestamp: 1 ensures earliest events come first for each user.

2. Step 2: Group by user and use $first and $last

   Using $first and $last after sorting picks the earliest and latest timestamps correctly.

3. Final Answer:

   [ { $sort: { timestamp: 1 } }, { $group: { _id: "$user", firstEvent: { $first: "$timestamp" }, lastEvent: { $last: "$timestamp" } } } ] -> Option A

4. Quick Check:

   Sort ascending + $first/$last = [ { $sort: { timestamp: 1 } }, { $group: { _id: "$user", firstEvent: { $first: "$timestamp" }, lastEvent: { $last: "$timestamp" } } } ] [OK]

Hint: Sort ascending before grouping to get correct first/last [OK]

Common Mistakes:

• Skipping $sort stage before $group
• Sorting descending when $first expects ascending
• Using $min/$max instead of $first/$last when order matters