You want to plot a 3D scatter plot where point colors represent a fourth variable. Which code correctly creates the 3D axes and applies color mapping?

hard📝 Application Q9 of 15

Matplotlib - 3D Plotting

Afig = plt.figure() ax = fig.add_subplot(111, projection='3d') sc = ax.scatter(x, y, z, c=colors, cmap='viridis') plt.colorbar(sc) plt.show()

Bfig = plt.figure() ax = plt.axes(projection=3d) ax.scatter(x, y, z, color=colors) plt.show()

Cfig = plt.figure() ax = fig.add_subplot(111) ax.scatter(x, y, z, c=colors) plt.show()

Dfig = plt.figure() ax = fig.add_subplot(111, projection='3d') ax.scatter(x, y, z) plt.colorbar() plt.show()

Step-by-Step Solution

Solution:

Step 1: Create 3D axes
Use fig.add_subplot(111, projection='3d') to enable 3D plotting.
Step 2: Scatter with color mapping
Pass the fourth variable as c=colors and specify a colormap with cmap='viridis'.
Step 3: Add colorbar
Use plt.colorbar(sc) to display the color scale.
Final Answer:
fig = plt.figure() ax = fig.add_subplot(111, projection='3d') sc = ax.scatter(x, y, z, c=colors, cmap='viridis') plt.colorbar(sc) plt.show() correctly implements all steps.
Quick Check:
Check for projection='3d', c=colors, and colorbar usage [OK]

Quick Trick: Use c=colors and plt.colorbar() with 3D axes [OK]

Common Mistakes:

Using projection without quotes
Omitting color mapping parameter
Calling colorbar without scatter reference

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More Matplotlib Quizzes

You want to plot a 3D scatter plot where point colors represent a fourth variable. Which code correctly creates the 3D axes and applies color mapping?

Step 1: Create 3D axes

Step 2: Scatter with color mapping

Step 3: Add colorbar

Final Answer:

Quick Check:

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