[Solved] What will the following code output?import seaborn as sns import matplotlib.pyplot as plt df = sns.load_dataset('tips') fig, ax = plt.subplots() sns.... | Matplotlib

Matplotlib - Seaborn Integration

What will the following code output?

import seaborn as sns
import matplotlib.pyplot as plt

df = sns.load_dataset('tips')
fig, ax = plt.subplots()
sns.scatterplot(data=df, x='total_bill', y='tip', ax=ax)
plt.title('Scatterplot on existing axes')
plt.show()

AA scatterplot of total_bill vs tip on a new figure with default title

BAn empty plot with no points

CA scatterplot of total_bill vs tip on the existing axes with custom title

DAn error because scatterplot cannot accept ax parameter

Step-by-Step Solution

Solution:

Step 1: Analyze code creating figure and axes
The code creates a figure and axes with plt.subplots() and stores axes in ax.
Step 2: Understand scatterplot with ax parameter
scatterplot is axes-level and plots on the given ax. Title is set on the figure.
Final Answer:
A scatterplot of total_bill vs tip on the existing axes with custom title -> Option C
Quick Check:
Axes-level plot on existing axes = scatterplot with ax= [OK]

Quick Trick: Axes-level plots use ax= to draw on existing axes [OK]

Common Mistakes:

Expecting scatterplot to create new figure automatically
Thinking ax= causes error with scatterplot
Assuming title applies only to figure-level plots

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More Matplotlib Quizzes

What will the following code output?

Step 1: Analyze code creating figure and axes

Step 2: Understand scatterplot with ax parameter

Final Answer:

Quick Check:

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