[Solved] Identify the error in this MATLAB code snippet:x = 0:0.1:1;y = sin(x);area = trapz(y,x); — Ans: Arguments to trapz are reversed; should be trapz(x,y) | MATLAB

MATLAB - Numerical Methods

Identify the error in this MATLAB code snippet:

x = 0:0.1:1;
y = sin(x);
area = trapz(y,x);

AArguments to trapz are reversed; should be trapz(x,y)

Bsin(x) should be sin(x.^2)

Ctrapz requires function handle, not vectors

Dx and y vectors must be same length

Step-by-Step Solution

Solution:

Step 1: Check trapz argument order
trapz syntax is trapz(x,y) where x is vector of points, y is function values.
Step 2: Identify mistake
Code uses trapz(y,x), reversing arguments, which leads to incorrect integration.
Final Answer:
Arguments to trapz are reversed; should be trapz(x,y) -> Option A
Quick Check:
trapz argument order matters = Arguments to trapz are reversed; should be trapz(x,y) [OK]

Quick Trick: trapz(x,y), x first then y values [OK]

Common Mistakes:

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