MATLAB - Linear Algebra
Consider the MATLAB code:
What is the correct output of
A = [1 2 3; 4 5 6]; N = null(A); disp(size(N));
What is the correct output of
size(N)?Consider the MATLAB code:
medium📝 Debug Q14 of 15
Step-by-Step Solution
Solution:
Step 1: Determine matrix size and rank
Matrix A is 2x3. Rank is 2 because rows are independent.Step 2: Calculate null space dimension
Null space dimension = number of columns - rank = 3 - 2 = 1. So null(A) returns a 3x1 matrix.Final Answer:
[3 1] -> Option AQuick Check:
Null space size = columns x (columns - rank) [OK]
Quick Trick: Null space columns = cols - rank [OK]
Common Mistakes:
- Confusing rows and columns in size
- Forgetting null space dimension formula
- Expecting null space to be square
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