You have temperature data temp = [15 18 21 24] measured at times time = [0 3 6 9] hours. How would you find the temperature at 4.5 hours using cubic interpolation in MATLAB?

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MATLAB - Numerical Methods

You have temperature data temp = [15 18 21 24] measured at times time = [0 3 6 9] hours. How would you find the temperature at 4.5 hours using cubic interpolation in MATLAB?

Ainterp1(time, temp, 4.5)

Binterp1(time, temp, 4.5, 'cubic')

Cinterp1(time, temp, 4.5, 'linear')

Dinterp1(temp, time, 4.5, 'cubic')

Step-by-Step Solution

Solution:

Step 1: Identify correct argument order and method
Syntax is interp1(x, y, xi, method). Here x=time, y=temp, xi=4.5, method='cubic'.
Step 2: Choose cubic interpolation
interp1(time, temp, 4.5, 'cubic') uses 'cubic' method correctly for smooth interpolation.
Final Answer:
interp1(time, temp, 4.5, 'cubic') -> Option B
Quick Check:
Use 'cubic' for smooth interp [OK]

Quick Trick: Use 'cubic' as 4th argument for smooth interp [OK]

Common Mistakes:

Swapping time and temp vectors
Using default linear instead of cubic
Omitting interpolation method argument

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You have temperature data temp = [15 18 21 24] measured at times time = [0 3 6 9] hours. How would you find the temperature at 4.5 hours using cubic interpolation in MATLAB?

Step 1: Identify correct argument order and method

Step 2: Choose cubic interpolation

Final Answer:

Quick Check:

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